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EastWind [94]
3 years ago
6

5-10m WHATS THIS ANSWER?. . . .. . .

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

-5 is the answer

Step-by-step explanation:

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Aisha runs a tutoring business. With Plan 1, students may choose to pay $26 per hour. With Plan 2, they may follow the plan show
Finger [1]

Answer:

$20 dollars and $10 dollars per hour

Step-by-step explanation:

the line starts at 20 and it escalates by 10 ( 10,20,30,40,50,ect)

i just had a question like this and i'm in middle school, i tried to look for the answer on here but no one answered so when i took time to answer the problem i got it right on the first try.. anyway i hope this helps .!

3 0
2 years ago
Write 3.617 correct to two decimal place
Sindrei [870]
We start with 3: it stays unchanged

3.


then the first decimal place also remains unchanged:

3.6


now the second decimal place:


3.61

does it remain unchanged? No! the number AFTER is is 5 or bigger (it's 7), so we need to round it up. the answer is this:

3.62
5 0
3 years ago
What is the remainder when
son4ous [18]
Can you take a picture instead ?
5 0
2 years ago
Read 2 more answers
If f(x)=x^2-7 and h(x)=7x-5, then f(h(2))=
zaharov [31]
We are given 3 equations. Using these equations we can find f(h(2)).

h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9

f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74

so f(h(2))=74
5 0
3 years ago
How do you find the value of c that satisfy the equation:
victus00 [196]

Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

<u>Step(i)</u>:-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

<u> Mean Value theorem</u>

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

f^{l} (c)  = \frac{f(b) -f(a)}{b-a}

<u>Step(ii):</u>-

Given  f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

          f¹(x) = 4(2x) +4(1) = 8x+4

<u>Step(iii)</u>:-

By using mean value theorem

f^{l} (c)  = \frac{f(0) -f(-1)}{0-(-1)}

8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}

8c+4 = -3-(-3)

8c+4 = 0

8c = -4

c = \frac{-4}{8} = \frac{-1}{2} = -0.5

c ∈ (-1,0)

<u>Conclusion</u>:-

The value of c = -0.5∈ (-1,0)

         

<u></u>

8 0
3 years ago
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