3 years ago

Find the radius of the circle if the center is at (1, 2) and the point (-3, 4) lies on the circle.

Mathematics

2 answers:

Alex3 years ago

8 0

Answer:

4.47

Step-by-step explanation:

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Anton [14]3 years ago

7 0

Answer:

2√5

Step-by-step explanation:

The radius is the distance from the center to a point anywhere along the edge of the circle. To find the distance between these two points, use the distance formula.

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(1--3)^2 + (2-4)^2}\\ d = \sqrt{4^2 + -2^2}\\ d = \sqrt{16 + 4}\\ d = \sqrt{20} \\d = 2\sqrt{5}$

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Pi owns a cornfield and has placed fences around four polls, A, B, C, D that delimit the edges of the field. He needs to drive a

olga2289 [7]

Answer:

52 miles

Step-by-step explanation:

A to B:

sqrt( (3 - (-2))^2 + (-11 - 1)^2 )

sqrt( (5)^2 + (-12)^2 )

sqrt( 25 + 144 )

sqrt( 169 )

B to C:

sqrt( (-2 - 3)^2 + (-23 - (-11))^2 )

sqrt( (-5)^2 + (-12)^2 )

sqrt( 25 + 144 )

sqrt( 169 )

C to D:

sqrt( (-7 - (-2))^2 + (-11 - (-23))^2 )

sqrt( (-5)^2 + (12)^2 )

sqrt( 25 + 144 )

sqrt( 169 )

D to A:

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sqrt( (5)^2 + (12)^2 )

sqrt( 25 + 144 )

sqrt( 169 )

Adding:

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8 0

2 years ago

the function of y= x^2 - 4x + 8 approximates the height y, of a bird and its horizontal distance, x as it flies from one fence p

Vika [28.1K]

Rewrite the given equation as
$y=x^2-4x+8=x^2-4x+4+4=(x-2)^2+4$ .
Since $(x-2)^2\ge 0$ , you can conclude that the imimum value of y will be gained for the minimum value of $(x-2)^2$ . The minimum value of $(x-2)^2$ is 0 for x=2.
So, y(2)=0+4=4.
Answer: minimum value of y is 4, when x=2.

7 0

2 years ago

Read 2 more answers

The equation for y=-2x+5 that is paralell passes through (1,-4)?

sattari [20]

0 beaxysabahagpannauqqu

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2 years ago

PLEASE HELP ME MAJOR TIME CRUNCH WILL GIVE BRAINLIEST TO CORRECT ANSWER PLUS 45 POINTS

Pepsi [2]

The correct answer is C.

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