2 years ago

Help pleaseeeeee ????

1 answer:

3 0

1) B
2) C
3) I think all of them equal 8

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masya89 [10]

We have to determine the complete factored form of the given polynomial

$f(x)=6x^3-13x^2-4x+15$ .

Let x= -1 in the given polynomial.

So, $f(-1)= 6(-1)^3-13(-1)^2-4(-1)+15 = -6-13+4+15 = 0$

So, by factor theorem

(x+1) is a factor of the given polynomial.

So, dividing the given polynomial by (x+1), we get quotient as $6x^2-19x+15$ .

So, $6x^3-13x^2-4x+15$ = (x+1) $6x^2-19x+15$ .

= $(x+1)(6x^2-10x-9x+15)$

= $(x+1)[ 2x(3x-5)-3(3x-5)]$

= $(x+1)(2x-3)(3x-5)$ is the completely factored form of the given polynomial.

Option D is the correct answer.

5 0

2 years ago

Vedmedyk [2.9K]

0.041 + 0.004
= 0.045
= 45/1000

8 0

2 years ago

AlekseyPX

Step-by-step explanation:

hi im not sure it's right it was kinda confusing

8 0

2 years ago

allochka39001 [22]

The number of times she has to fill it up is 2 times

4 0

2 years ago

Aneli [31]

Plug in -1 for x and work it ou'

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

= -1 + 6 - 12 + 8

= 1

8 0

2 years ago