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Mathematics

2 answers:

lianna [129]3 years ago

5 0

Answer:

3>x

Step-by-step explanation:

finlep [7]3 years ago

3 0

Answer:

less than 3 (x < 3)

Step-by-step explanation:

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Which of the following equations has the same solutions as the equations 3x+2y=-12

Marianna [84]

B, C, E, F

<h2>Explanation:</h2>

In this problem, we have the following equation of a line written in Standard form:

$3x+2y=-12$

So we need to choose the equations that has the same solutions as this equation. If we multiply each equation by a constant term and find the same solution as the given equation, then they will have the same solution. This is only true fro options B, C, E and F.

Option B.

$-3x-2y= 12 \\ \\ Multiply \ both \ sides \ by \ -1: \\ \\ (-1)(-3x-2y)=(-1)(12) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option D.

$15x+10y= -60 \\ \\ Multiply \ both \ sides \ by \ 1/5: \\ \\ (\frac{1}{5})(15x+10y)=(\frac{1}{5})(-60) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option E.

$6x+2y= -12 \\ \\ Multiply \ both \ sides \ by \ 1/2: \\ \\ (\frac{1}{2})(6x+2y)=(\frac{1}{2})(-24) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option F.

$1.5x+y= -6 \\ \\ Multiply \ both \ sides \ by \ 2: \\ \\ (2)(1.5x+y)=(2)(-6) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

For the other options, there is no any constant term that multiplies both sides of the equation and gives us the same given equation.

<h2>Learn more:</h2>

About this subject: brainly.com/question/8810210

#LearnWithBrainly

7 0

3 years ago

The area of the sector of a circle with a radius of 8 centimeters is 125.6 square centimeters. The estimated value of pi is 3.14

tangare [24]

$\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta\pi r^2}{360}\qquad 
\begin{cases}
\theta=\textit{angle in degrees}\\
r=radius\\
----------\\
r=8\\
A=125.6
\end{cases}
\\\\\\
360A=\theta\pi r^2\implies \cfrac{360A}{\pi r^2}=\theta\implies \cfrac{360\cdot 125.6}{\pi 8^2}=\theta$