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aliya0001 [1]
4 years ago
15

Using a straightedge and compass, construct the perpendicular bisector of FG

Mathematics
1 answer:
Maurinko [17]4 years ago
5 0
This is how I learned.
Place a point above the line segment.  Open the compass so that you can create arcs on the line segment.  One arc should intersect on the right side, the other on the left.  Name these points (A and B, for example). Move the compass to one point.  Use the same radius in the compass<em /><em /> and make an arc below the line segment.  Then move the compass to the opposite point and make another arc (with the same radius).  The two arcs should intersect.  Draw a line from the point above the line segment to the new intersection and you have your perpendicular bisector. 
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Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

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7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

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