The ratio of T1 : T2 is 1.6
<h3>What is Simple Harmonic Motion ?</h3>SHM is the periodic motion of a particle along a line such that the acceleration of the body is directed toward a fixed point and proportional to its displacement.
Given that a pendulum of length 130.0 cm has a period of oscillation, T₁.
Then, The period T₁ = 2
T₁ = 2 x 3.142
T₁ = 6.284 x 0.36
T₁ = 2.266
But if T = 0
then, m /r = mg
the m will cancel out
Then v =
where r = 50/100 = 0.5m
Substitute into the formula
v =
v = 2.24 m/s
Also, given that the bob is pulled and released to move in a horizontal circle of radius 50.0 cm and the period of rotation is T2,
w = 2f
w = 2/T
but v = wr
w = v/r
Therefore,
v/r = 2/T
Substitute all the parameters into the formula
2.24/0.5 = (2 x 3.1423) /T
T = 6.284/4.472
T = 1.405 =
The ratio T₁: T2 will be 2.266/1.405
The ratio is 1.6
Learn more about Simple Harmonic Motion here: brainly.com/question/24646514
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