Answer:
b. -11.6 cm
Explanation:
We have given parameters:
Length, l = 1.5 m = 150 cm
Mass of weight, 
= 20 kg
Width, x = 4 cm
Distance d = 4 cm
Mass of bar, 
= 5 kg
We are asked to find the center of mass from the mid-point, 
Since 3 weights are on the left and 2 weights are on the right, we know:
= 3 * 20 = 60 kg
= 2 * 20 = 40 kg
And also we know that, 
= 150/2 = 75 cm
For the left side, center of mass is:
cm
From the midpoint, the distance to the left is:
cm
For the right side, center of mass is:
cm
From the midpoint, the distance to the right will be:
cm
Hence,
cm
The most reliable form of identifying potentially effective reinforcers is known as Preference Assessment. It is an adaptive procedure vastly used in the field of reinforcers.
Explanation:
Preference Assessment identifies items that are likely to be effective as reinforcers by identifying a particular learner's preference for them.
- Reinforcement is an important part of being an effective behavior technician and the preference assessments are crucial.
- Plenty of research has shown that when you give the learner an opportunity to show you what they want that is a much better indication of what will work as a reinforcer rather than asking family.
- Preference assessments identify attention, objects or activities that have a strong potential for serving as reinforcers for target clients. There are ethical reasons to use them.
- Beyond the scope of the guide is the exhaustive review of the Preference assessment methodology and literature. However, interested readers go through Virus-Ortega et al(2014) for decision- making process and selecting an appropriate method of preference assessment for individuals with disabilities.
Answer:
The magnitude of the centripetal acceleration increases by 16 times when the linear speed increases by 4 times.
Explanation:
The initial centripetal acceleration, a of the race-car around the circular track of radius , R with a linear speed v is a = v²/R.
When the linear speed of the race-car increases to v' = 4v, the centripetal acceleration a' becomes a' = v'²/R = (4v)²/R = 16v²/R.
So the centripetal acceleration, a' = 16v²/R.
To know how much the magnitude of the car's centripetal acceleration changes, we take the ratio a'/a = 16v²/R ÷ v²/R = 16
a'/a = 16
a' = 16a.
So the magnitude of the centripetal acceleration increases by 16 times when the linear speed increases by 4 times.
When you touch<span> a doorknob (or something else made of metal), which has a positive charge with few electrons.</span>
D
The student's conclusion shows experimental bias
Just because most of nis classmates like puffed cereal ,it is inappropriate to conclude puffed cereal is better than oats cereal
