The answer is 1/20 .............
The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then

For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is

The distribution is graphed as shown below.
Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.
Answer:
1). t ≥ -
2). k ≥ 
3). y < -
4). b > 
5). w ≤ 0
Step-by-step explanation:
1). 




t ≥ -
2). 15k + 11 ≤ 18k - 5
15k - 18k ≤ -5 - 11
-3k ≤ - 16
3k ≥ 16
k ≥ 
3). 44y > 11 + 88y - 22y
44y > 11 + 66y
44y - 66y > 11
-22y > 11
22y < -11

y < 
4). 

(b - 27) > 
b > 
b > 
5). 11w - 8w ≥ 14w
3w - 14w ≥ 0
-11w ≥ 0
w ≤ 0
(-5/3)•(-6/1)=(30/3)
(30/3) simplified is (10/1)