The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles
<h3>Balanced equation </h3>
2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
<h3>How to determine the theoretical yield of NaBr</h3>
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
Therefore,
2.36 moles FeBr₃ will react to produce = (2.36 × 6) / 2 = 7.08 moles of NaBr
Therefore,
Thus, the theoretical yield of NaBr is 7.08 moles
Learn more about stoichiometry:
brainly.com/question/14735801
#SPJ1
The ether that is formed when ethyl alcohol is heated in the presence of sulfuric acid that is concentrated is called diethyl ether. Heating the alcohol breaks the bond between the R group and the OH group forming an ether. The formula of the ether would be CH3CH2OCH2CH3.
This is tue for many reasons help this works
Answer:
<u>20.25 mL.</u>
Explanation:
The volume of base required for the titration can be derived by removing the base titrant volume from the volume at endpoint.
i.e Final volume - initial volume
= (22.08 - 1.83)mL
<u>= 20.25 mL.</u>
<em>(Repeat and average volume results for accuracy.)</em>