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krek1111 [17]
3 years ago
5

uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read

the base titrant volume as 1.83 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 22.08 mL. What volume of base was required for the titration?
Chemistry
1 answer:
victus00 [196]3 years ago
5 0

Answer:

<u>20.25 mL.</u>

Explanation:

The volume of base required for the titration can be derived by removing the base titrant volume from the volume at endpoint.

i.e Final volume - initial volume

= (22.08 - 1.83)mL

<u>= 20.25 mL.</u>

<em>(Repeat and average volume results for accuracy.)</em>

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A 100. 0 ml sample of 0. 10 m nh3 is titrated with 0. 10 m hno3. Determine the ph of the solution after the addition of 100. 0 m
DerKrebs [107]

The pH of the solution after the addition of 100. 0 ml of HNO3. The kb of NH3 is 1. 8 × 10-5. So, pH is 10.9 basic .

This neutralization occurs as the acid is added to the base:

NH3(aq)+ HNO3(aq)= NH4NO3(aq)+ H2O(l)

The initial moles of NH3present is given by,

nNH3= c×v= 0.10× 100/1000= 0.01m

The number of moles of

HNO3 added is given by:

nHNO3= c×v= 0.10× 100/1000= 0.001

It is clear from the equation that the acid and base react in a 1:1 molar ratio. So, the no. moles of NH3remaining will be 0.01 - 0.001= 0.009

The total volume is now

100.0+100.0= 200.0x cm3

The concentration of NH3 is given by,

[NH3]= c/v= 0.001/200/1000= 0.05x mol/l .

pOH= 12 (pKb− logb)

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Given that there is little dissociation, we can roughly compare this to the starting concentration.

pKb= −logKb= −log(1.8×10−5)= 4.744

pOH= 3.056

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pH= 14− 3.056= 10.9

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8 0
1 year ago
. How many grams of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide? ____Cl
dlinn [17]

Answer: 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide.

Explanation:

The balanced chemical reaction is;

Cl_2+MgBr_2\rightarrow MgCl_2+Br_2

Cl_2 is the limiting reagent as it limits the formation of product and MgBr_2 is the excess reagent.

According to stoichiometry :

1 mole of Cl_2 produces = 1 mole of MgCl_2

Thus 2 moles of Cl_2 will produce=\frac{1}{1}\times 2=2moles  of MgCl_2

 Mass of MgCl_2=moles\times {\text {Molar mass}}=2moles\times 95g/mol=190g

Thus 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide

5 0
3 years ago
3.604m + 104.29m + 3.1m + 17.41m. The sum expressed in the correct number of significant figures is
dedylja [7]

Answer:

128.4 m

Explanation:

3.604m + 104.29m + 3.1m + 17.41m

Add all the values

= 128.404 m

The significant figure rule for addition is for the sum to have the same number of decimal places as the value with the least number of decimal places. In the addition sentence 3.604m + 104.29m + 3.1m + 17.41m, the value with the least number of decimal places is 3.1, which has 1 decimal place. Therefore, we round our sum so that it also has 1 decimal place.

128.404 m

= 128.4 m

I hope this helps!

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3 years ago
What’s a physical change in the movie theader
kirill [66]
A physical change that may happen in a movie theater is:

You accidentally step on a piece of popcorn.

That piece of popcorn is still made up of the same things but LOOKS different. Therefore, the piece of popcorn went through a physical change.

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6 0
3 years ago
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Answer:

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Explanation:

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