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Maurinko [17]
3 years ago
9

Sort these species into isoelectronic groups. It doesn\'t matter which group goes in which box, so long as the correct species a

re grouped.
He
Be2+
Li+
N3-
Ne
S2-
Mg2+
Ti4+
K+
Chemistry
1 answer:
OleMash [197]3 years ago
7 0

Answer : The isoelectronic groups are:

He,Be^{2+},Li^{+}

N^{3-},Mg^{2+}

S^{2-},Ti^{4+},K^{+}

Explanation :

Isoelectronic : It is defined as the compound or molecule having the same number of electrons and the same number of electronic structure.

  • The element is helium. The number of electrons are 2.
  • The element is beryllium. The number of electrons are 4. The number of electrons in Be^{2+} = 4 - 2 = 2
  • The element is lithium. The number of electrons are 3. The number of electrons in Li^{+} = 3 - 1 = 2
  • The element is nitrogen. The number of electrons are 7. The number of electrons in N^{3-} = 7 + 3 = 10
  • The element is neon. The number of electrons are 10.
  • The element is sulfur. The number of electrons are 16. The number of electrons in S^{2-} = 16 + 2 = 18
  • The element is magnesium. The number of electrons are 12. The number of electrons in Mg^{2+} = 12 - 2 = 10
  • The element is titanium. The number of electrons are 22. The number of electrons in Ti^{4+} = 22 - 4 = 18
  • The element is potassium. The number of electrons are 19. The number of electrons in K^{+} = 19 - 1 = 18

The isoelectronic groups are:

He,Be^{2+},Li^{+}

N^{3-},Mg^{2+}

S^{2-},Ti^{4+},K^{+}

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Can we cover the earth with one mole of pennies? Explain.
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Answer:

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A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.
MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

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= 1020 g/l

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Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

A.

Density of sucrose = mass/volume

= molar mass/molar concentration

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= 85.6 g/l

Number of moles = mass/molar mass

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= 0.25 mol

B.

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

C.

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

6 0
3 years ago
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