Answer:
Energy absorbed by <u>Iron block</u> E (iron) = 460.5 J
Energy absorbed by <u>Copper block</u> E (Copper) = 376.8 J
Explanation:
To find the heat absorbed, we can use the formula as,
<em>q = m c ΔT</em>
Here, Mass = m = 10 g = 0.01 kg
ΔT = change in temperature = 400 - 300 = 100 K = 100 - 273 = -173 °C
c = specific heat capacity
c for iron = 460.5 J/kg K
c for copper = 376.8 J/kg K
Plugin the values in the above equation, we will get,
<em>q (iron) = 0.01 kg × 460.5 J/kg K × 100 K = 460.5 J</em>
<em>q (copper) = 0.01 kg × 376.8 J/kg K × 100 K = 376.8 J</em>
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Answer:
The molar mass of the acid is 167.5 g/mol
Explanation:
A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed a single end point after 19.31 mL of 0.1243 M NaOH had been introduced. Calculate the molecular mass of the acid.
Step 1: Data given
Mass of the sample of a purified organic acid = 0.4021 grams
Molarity = 0.1243 M
Volume needed to reach the end point = 19.1 mL = 0.01931 L
Step 2: Calculate the number of moles NaOH
Moles NaOH = molarity NaOH * volume
Moles NaOH = 0.1243 M * 0.01931 L
Moles NaOH = 0.00240 moles
Step 3: Calculate moles of the acid
We'll need 0.00240 moles of acid to neutralize 0.00240 moles of NaOH ( it's a single end point)
Moles acid = 0.00240 moles
Step 4: Calculate molar mass of the acid
Molar mass = mass / moles
Molar mass = 0.4021 grams / 0.00240 moles
Molar mass = 167.5 g/mol
The molar mass of the acid is 167.5 g/mol
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