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Alex
3 years ago
12

Graph y= –3x+4. (I WILL MARK BRAINLIEST)

Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

Answer:

See attached

Step-by-step explanation:

<u>Given function:</u>

  • y= –3x + 4

To graph the line we need two points

One of the easy points is the y-intercept:

  • (0, 4)

Another point can be taken depending on the slope. With the slope of -3, we select x = 2 and find its y- coordinate:

  • y = -3(2) + 4 = -6 + 4 = -2

So we have points

  • (0, 4) and (2, -2)

Plot these points and connect with the line and we are done.

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The vertex form of  f(x)=ax^2+bx+c
f(x)=a(x-h)^2+k

where: h=\dfrac{-b}{2a};\ k=f(h)

We have:  f(x)=x^2-6x+13\to a=1;\ b=-6;\ c=13

substitute:
h=\dfrac{-(-6)}{2\cdot1}=\dfrac{6}{2}=3\\\\k=f(3)=3^2-6\cdot3+13=9-18+13=4
The vertex form of f(x):
f(x)=(x-3)^2+4
The value of minimum is equal k.
Therefore:  y_{min}=4



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