Answer:
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
Step-by-step explanation:
The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z
Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
I don't understand. What are the values given? Are they values of an x,y plot?
If you plot them they are a straight line with y =6x - 2.9 but I don't know what you mean by when x=3 and y = 4?
We are given with the expression <span>tan2x / x</span> and asked to evaluate the expression to limit as theta approaches zero. In this case, we substitute first zero. The answer is zero over zero. This is indeterminate so we derive the terms accdg to L'hopital's rule. The derivative is 2 sec^2 2x/1. cos 2x is 1 so is sec^2 2x. Hence the answer is 2.
The line goes down 3 over to the right 4
-3/4
Choice B
The slope is -500. The bird descends......
3 boxes are filled every 4 minutes
.75 boxes are filled per minute
3 laps per minute is line B
Answer:
y = 2x -8
Step-by-step explanation:
The slope intercept form for a line is
y = mx+b where m is the slope and b is the y intercept
y = 2x -8
