The equation computed shows that the numbers will be 9, 11 and 13.
<h3>How to illustrate the information?</h3>
Let the numbers be:
First number = x
Second number = x + 2,
Third number = x + 4.
Total of the numbers = 33
The equation will be:
= first + second + third number
x + x + 2 + x + 4 = 33
3x + 6 = 33
Collect like terms
3x = 33 - 6
3x = 27.
Divide both side by 3
3x/3 = 27/3
x = 9
First number = x = 9
Second number = x + 2 = 9 + 2 = 11
Third number = x + 4. = 9 + 4 = 13
The numbers will be 9, 11, and 13.
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Illustrate the equation to find three consecutive odd integers whose sum is 33.
X + y = 1
x + 3y = 9
Subtract the second equation from the first.
-2y = -8
divide both sides by -2
y = 4
Plug 4 back into either equation and solve for x.
x + y = 1
x + 4 = 1
subtract 4 from each side
x = -3
(-3, 4)
Hey there!☺
In our first step, we will simplify both sides of the equation:
Now subtract 4 from both sides:
In our last step, we will divide both sides by -2:
x=-7/2 is your answer.
Hope this helps!☺
Answer:
<em>
x−y
=
9
, x
+
y
=
6</em>
<em>x
+
y
=
4 , x
−
y
=
2</em>
<em>x
+
2
y
=
4 , x
−
y
=
−
3 </em>
<em>try out these examples?</em>
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