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2 years ago

A store pay $120 for a bicycle. The store has a 60% markup policy. What is the selling price of the bicycle?

Mathematics

2 answers:

Zielflug [23.3K]2 years ago

7 0

The selling price will be $192

$120 x 60% = $72 markup

$120 + $72 = $192

iragen [17]2 years ago

7 0

Answer:

$192

Step-by-step explanation:

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Find a value of x that makes the equation true:<br> -(-2x + 1) = 9 – 14x

luda_lava [24]

Answer:

x=0.625

Step-by-step explanation:

-(-2x+1)=9-14x

distribute:

2x-1=9-14x

add 1 to both sides

2x = 10-14x

add 14x to both sides

16x=10

divide by 16 to isolate x

x = 0.625

check:

-(-2(0.625)+1) = 9-14(0.625)

0.25 = 0.25

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2 years ago

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you were given 15$ from your auntie to go to the mall. you spend 6$ on snacks, and 5$ on shirt on your way to the car,you found

Finger [1]

The answer would be 14

Explanation:
If you look on a number line and start from 15 then from there you minus 6 which equals 9 then you minus 5 which equals 4 and add 10 which equals 14 and that 14 is on the positive side of the number line. So 14 is your answer.

5 0

3 years ago

Giải phương trình sau:<br> sinx=1/2

cupoosta [38]

Answer: $\begin{bmatrix}\mathrm{Radians:}\:&\:x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi n\:\\ \:\mathrm{Degrees:}&\:x=30^{\circ \:}+360^{\circ \:}n,\:x=150^{\circ \:}+360^{\circ \:}n\end{bmatrix}$

Step-by-step explanation:

$\sin \left(x\right)=\frac{1}{2}$

$x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi$

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2 years ago

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Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

What is the average rate of change of the amount of the element over the 10-minute experiment? *

Dima020 [189]

Answer:

$-2.7 g/min$

Step-by-step explanation:

Given: a graph

To find: the average rate of change of the amount of the element over the 10-minute experiment

Solution:

A rate of change of one quantity with respect to another quantity is known as rate of change. If y is the dependent variable and x is the independent variable then average rate of change = change in y /change in x.

From the graph,

change in x (time) = $10-0=10$ minutes

change in y ( amount of the element) = $3.22-30=-26.78$ g

So, average rate of change = $\frac{-26.78}{10} =-2.7 g/min$

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3 years ago