Answer:
Step-by-step explanation:
Given
See attachment for matrix
From the attachment, we have the following vertices
When scaled by 3T, we have the following:
Hence, the vertices are:
Answer: The 1st one is 1 soultion the 2nd one is 1 soultion the 3rd one is multiple soultion and the last one is multiple solution
Step-by-step explanation: hope I am right?
We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
