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3 years ago

Match each explicit formula to its corresponding recursive formula.

Mathematics

1 answer:

Murrr4er [49]3 years ago

3 0

Answer:

See attached

Step-by-step explanation:

The answer is in below picture

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Given that ƒ(x) = x2 + 1 and g(x) = –3, multiply the functions (g · ƒ)(x). Question 8 options: A) (g · ƒ)(x) = –3x2 – 3 B) (g ·

vesna_86 [32]

Answer:

Step-by-step explanation:

We are given the two functions:

$f(x)=x^2+1\text{ and } g(x)=-3$

And we want to find:

$(g\cdot f)(x)$

This is equivalent to:

$=g(x)\cdot f(x)$

Substitute:

$=(-3)\cdot (x^2+1)$

Distribute:

$=-3x^2-3$

Therefore:

$(g\cdot f)(x)=-3x^2-3$

So, our answer is A.

5 0

2 years ago

Factorise 3x^2+13x+4 by splitting the middle term

mihalych1998 [28]

Answer:

( x + 4 ) ( 3x + 1 )

Step-by-step explanation:

→ Identify the product, sum & factors

Product = 4

Sum = 13

Factors = 4 & 1

3x² + 12x + x + 4

→ Factorise 3x² + 12x and x + 4

3x² + 12x ⇔ 3x ( x + 4 )

x + 4 ⇔ 1 ( x + 4 )

→ Take out the ( x + 4 ) as a factor and ( 3x + 1 )

( x + 4 ) ( 3x + 1 )

4 0

3 years ago

Which point is on the line y=-2x+ 3?

Dmitrij [34]

Answer: (3, -3)

Step-by-step explanation:

You substitute each point into the function and see if it fits:

(-2, -1) ⇒ -2(-2) + 3 = 4 + 3 = 7 ≠ -1

(3, -3) ⇒ -2(3) + 3 = -6 + 3 = -3

(3, 3) ⇒ -2(3) + 3 = -6 + 3 = -3 ≠ 3

(-3, -9) ⇒ -2(-3) + 3 = 6 + 3 = 9 ≠ -9

4 0

3 years ago

Read 2 more answers

Simplify cotø(tanø+cotø)

Sladkaya [172]

Answer:

$\large\boxed{\cot\theta(\tan\theta+\cot\theta)=1+\cot^2\theta=\dfrac{1}{\sin^2\theta}=\csc^2\theta}$

Step-by-step explanation:

$\text{Use}\\\\\text{distributive property:}\ a(b+c)=ab+ac\\\cot\alpha\tan\alpha=1.\\\\======================\\\\\cot\theta(\tan\theta+\cot\theta)=(\cot\theta)(\tan\theta)+(\cot\theta)(\cot\theta)\\\\=1+\cot^2\theta\\\\\text{If you want next transformation, then use:}\\\\\cot\alpha=\dfrac{\cos\alpha}{\sin\alpha}\\\\\sin^2\alpha+\cos^2\alpha=1\\\\=======================$

$=1+\left(\dfrac{\cos\theta}{\sin\theta}\right)^2=1+\dfrac{\cos^2\theta}{\sin^2\theta}=\dfrac{\sin^2\theta}{\sin^2\theta}+\dfrac{\cos^2\theta}{\sin^2\theta}=\dfrac{\sin^2\theta+\cos^2\theta}{\sin^2\theta}\\\\=\dfrac{1}{\sin^2\theta}\\\\\text{If you want next transformation, then use:}\\\\\csc\alpha=\dfrac{1}{\sin\alpha}\\\\=\left(\dfrac{1}{\sin\theta}\right)^2=(\csc\theta)^2=\csc^2\theta$

4 0

3 years ago

A pizza parlor offers 5 different pizza toppings. How many different kinds of 2-topping pizzas are available?

Gelneren [198K]

So let's pretend there is olives, pepperoni, jalapenos, sausage, and pineapple. Here is an example of an outcome chart that is useful when it comes to these type of problems.

sausage
l
pineapple-olives-pepperoni
l
jalapenos

1. Olives and sausages
2. olives and pepperoni
3. olives and jalapenos
4. olives and pineapple
5. sausages and pepperoni
6. sausages and jalapenos
7. sausage and pineapple
8. pepperoni and jalapenos
9. pepperoni and pineapple
10. pineapple and jalapenos

There are 10 total 2 topping pizzas possible.

Now I'm hungry...

Hope this helps!

8 0

3 years ago