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cupoosta [38]
2 years ago
8

Which quadratic equation has roots –2 and 1/5?

Mathematics
1 answer:
AysviL [449]2 years ago
4 0

Answer:

The equation 5x^2\:+\:9x\:-\:2\:=\:0 has roots –2 and 1/5.

Hence, the option 'a' is the correct answer.

Step-by-step explanation:

Checking the equation

5x^2\:+\:9x\:-\:2\:=\:0

putting x = -2 in the equation

5\left(-2\right)^2\:+\:9\left(-2\right)-\:2\:=\:0\:

2^2\cdot \:\:5-9\cdot \:\:2-2=0

2^2\cdot \:5-18-2=0

20-20=0

0=0

L.H.S=R.H.S

putting x = 1/5 in the equation

5\left(\frac{1}{5}\right)^2\:+\:9\left(\frac{1}{5}\right)-\:2\:=\:0\:

5\left(\frac{1}{5}\right)^2+9\cdot \:\frac{1}{5}-2=0

\frac{1}{5}+\frac{9}{5}-2=0

2-2=0

0=0

L.H.S=R.H.S

As putting x = -2 and x = 1/5 satisfy the equation.

Therefore, the equation 5x^2\:+\:9x\:-\:2\:=\:0 has roots –2 and 1/5.

Hence, the option 'a' is the correct answer.

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SVEN [57.7K]

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122

Step-by-step explanation:

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Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
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__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

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3 years ago
En una olimpiada matemática, cada estudiante recibe un punto por cada pregunta acertada. En la siguiente tabla de frecuencias se
Leviafan [203]

La tabla relacionada con la pregunta se puede encontrar en la imagen adjunta a continuación:

Responder:

70%

Explicación paso a paso:

probabilidad de seleccionar aleatoriamente a un participante que haya obtenido entre 71 y 85 puntos:

Probabilidad = resultado requerido / Total de resultados posibles

Resultados posibles totales = Sumando la frecuencia para obtener el número total de estudiantes = (9 + 12 + 12 + 18 + 9) = 60 estudiantes

Resultado requerido:

Clase :

(71 - 75) = frecuencia = 12

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(81 - 85) = frecuencia = 18

Total = (12 + 12 + 18) = 42 = resultado requerido

Por tanto, P = 42/60 = 0,7 = (0,7 * 100%) = 70%

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castortr0y [4]

Answer:

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Step-by-step explanation:

Since a clothes shop has some special offers, for which T-shirts are buy one get one free and jumpers are 3 for 2, and the normal price of a T-shirt is £ 4.80 and the normal price of a jumper is £ 14.60, to determine how much does it cost to get 5 jumpers and 4 T-shirts using this offer as appropriate, the following calculation must be performed:

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Therefore, the cost of 5 jumpers will be £ 58.40 (one more can be taken for free), the cost of 4 T shirts will be £ 9.60, and the total cost of the purchase will be £ 68.

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This rearranges to x^2 = 40

x = 40 = 2sqrt(10)

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