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3 years ago

⚠️HELP ME OUT PLS⚠️

Mathematics

2 answers:

Katena32 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Sedaia [141]3 years ago

5 0

The answer is B.
Explanation: A doesn’t make sense because he only has 3 tries not 4. C doesn’t make sense because he tried 3 times not 2 times

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2(4x – 3) ≥ –3(3x) + 5x?Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8?

nika2105 [10]

Answer:

x<=-1/2

Step-by-step explanation:

An inequality is a mathematical relationship that compares two unequal numbers using the number line

To solve the inequality 2x – 6 ≥ 6(x – 2) + 8

We first simplify both sides of the inequality

2x-6≥6x-12+8

2x-6≥6x-4

Add 6 to both sides

2x≥6x+2

-4x≥2

x≥2/-4

Sign changes when we divide both sides of equation by a negative sign

x<=-1/2

Therefore x is less than or equal to -1/2 on the number line

5 0

3 years ago

What is the slope of the line that passes through (2, 12) and (4, 20)?On the graph of the equation 3x + 2y = 18, what is the val

Paha777 [63]

Answer: The slope of the line that passes through (2, 12) and (4, 20) is 4.

The value of the y-intercept is 9.

Step-by-step explanation:

Slope of line passing through (a,b) and (c,d) = $\dfrac{d-b}{c-a}$

Then, the slope of the line that passes through (2, 12) and (4, 20) = $\dfrac{20-12}{4-2}$

$=\dfrac{8}{2}=4$

So, the slope of the line that passes through (2, 12) and (4, 20) is 4.

To find the y-intercept of 3x + 2y = 18, first write in slope intercept form y=mx+c ( where c= y-intercept ).

$2y=-3x+18\\\\\Rightarrow\ y=-\dfrac{3}{2}x+9$

By comparison, c= 9

Hence, the value of the y-intercept is 9.

4 0

3 years ago

Every person has blood type O, A, B, or AB. A random group of people are blood-typed, and the results are shown in the table.

vova2212 [387]

The probability that a randomly chosen person from this group has type B is 3/25

The probability that a randomly chosen person from this group has type AB is 1/25

The probability that a randomly chosen person from this group has type B or type AB blood is 4/25

8 0

3 years ago

Read 2 more answers

Please help is for now

cupoosta [38]

3 because I did the quiz and got it right txt me if you need help

8 0

3 years ago

Read 2 more answers

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

3 0

3 years ago