The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).
Here, b = 18 cm and h = 9 cm. Thus, the desired area is:
(18 cm)(9 cm)
A = ----------------------- = 81 cm^2
2
This problem gives you more info than is needed to solve it. The area of the given triangle is 81 cm^2.
Answer: x=−2
Step-by-step explanation:
Let's solve your equation step-by-step.
4(8−x)−32=98−5(3x+24)
Step 1: Simplify both sides of the equation.
4(8−x)−32=98−5(3x+24)
(4)(8)+(4)(−x)+−32=98+(−5)(3x)+(−5)(24)(Distribute)
32+−4x+−32=98+−15x+−120
(−4x)+(32+−32)=(−15x)+(98+−120)(Combine Like Terms)
−4x=−15x+−22
−4x=−15x−22
Step 2: Add 15x to both sides.
−4x+15x=−15x−22+15x
11x=−22
Step 3: Divide both sides by 11.
11x
/11
=
−22
/11
x=−2
The perimeter of a rectangle is 2*L+2*W. Knowing that length is 99, we do 2*99 to get 198.Do 374-198, which is 176, we know that that is twice the length of the width. Therefore the width is 176/2, which is 88.
75% because 9/12 simplified is 3/4 which is 75%
