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3 years ago

The ages of the students in a dance class are 10, 9, 11, 12, 9, 10, 9, 10, 11, 12, 8, 12, 12.

Mathematics

2 answers:

faust18 [17]3 years ago

8 0

Answer:

Put the numbers in order then find the number that appears the most which is 12.

Step-by-step explanation:

Dominik [7]3 years ago

6 0

Answer:

I don't understand your question but if you wanted to know the mean, median, mode, here it is:

Mean: 10.384615384615

Median: 10

Mode: 12

Range: 4

Minimum:8

Maximum:12

# count: 13

Sum: 135

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Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

6 0

2 years ago

Which is not a point of concurrency in a triangle?

Wewaii [24]

F incenter hope this helps

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3 years ago

What does number eleven want me to do exactly?

neonofarm [45]

(x+7, y-3)
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8 0

2 years ago

Read 2 more answers

Which expression has the same value as the one below ?<br><br> 50 + (-17)

irina [24]

Answer:

=33

Step-by-step explanation:

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2 years ago

Can u tell me which one is the median in here??

ki77a [65]

Answer:

-1

Step-by-step explanation:

To calculate the median, you select the middle number. So first, we must put the numbers in order

-23, -20, -16, -<u>1,</u> -1, 10, 10

The middle number is -1. (there are 3 numbers either side)

4 0

3 years ago