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andrew11 [14]
2 years ago
14

Tickets to a science Museum cost $19.95 each there is a three dollar charge for each order no matter how many tickets are ordere

d right and equation for each course and dollar of ordering tickets then find The total cost if you order five tickets
Mathematics
1 answer:
denis23 [38]2 years ago
8 0
If the three dollars isn't charged onto each ticket the answer should be $102.75
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PLEASE HELP!!!!! I NEED THIS FAST!!!!!!
ioda
Who says V1=V2?
if we simplify we get
(2/3)pir₁³=12pir₂²
for V1 to equal V2


a.
solve for r₁ to find r₁ as a function of r₂
(2/3)pir₁³=12pir₂²
times 3/2 both sides and divide by pi
r₁³=18r₂²
cube root both sides
r₁=∛(18r₂²)

if solve for r₂
(2/3)pir₁³=12pir₂²
divide by 12pi both sides
(1/18)r₁³=r₂²
squer root both sides
√((1/18)r₁³)=r₂



double radius of pond which is r1
√((1/18)r₁³)=r₂
r₁ turns to 2r₁ to double radius
√((1/18)(2r₁)³)=r₂double
√(8(1/18)(r₁)³)=r₂double
(√8)(√((1/18)(r₁)³))=r₂double
√((1/18)r₁³)=r₂ so
(√8)(r₂)=r₂double
(2√2)(r₂)=r₂double
the radius of the tank is multipled by 2√2
5 0
3 years ago
Complete the table of values
Agata [3.3K]
Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify! 

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, 3^{-2} =
\frac{1}{3^{2} }.
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, (\frac{3}{4}) ^{3}  =  \frac{ 3^{3} }{4^{3} }.
3) The zero exponent rule<span> says that any number raised to zero is 1. For example, 3^{0} = 1.
</span>

Back to the Problem:
Problem 1 
The x-values are in the left column. The title of the right column tells you that the function is y =  4^{-x}. The x-values are:
<span>1) x = 0
</span>Plug this into y = 4^{-x} to find letter a:
y = 4^{-x}\\&#10;y = 4^{-0}\\&#10;y = 4^{0}\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = 4^{-x} to find letter b:
y = 4^{-x}\\ &#10;y = 4^{-2}\\ &#10;y =  \frac{1}{4^{2}} \\  &#10;y= \frac{1}{16}
<span>
3) x = 4
</span>Plug this into y = 4^{-x} to find letter c:
y = 4^{-x}\\ &#10;y = 4^{-4}\\ &#10;y =  \frac{1}{4^{4}} \\  &#10;y= \frac{1}{256}
<span>

Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is y =  (\frac{2}{3})^x. The x-values are:
<span>1) x = 0
</span>Plug this into y = (\frac{2}{3})^x to find letter d:
y = (\frac{2}{3})^x\\&#10;y = (\frac{2}{3})^0\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = (\frac{2}{3})^x to find letter e:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\&#10;y =  \frac{4}{9}
<span>
3) x = 4
</span>Plug this into y = (\frac{2}{3})^x to find letter f:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}
<span>
-------

Answers: 
a = 1
b = </span>\frac{1}{16}<span>
c = </span>\frac{1}{256}
d = 1
e = \frac{4}{9}
f = \frac{16}{81}
5 0
3 years ago
Can someone help me please
fredd [130]
The answer to that is C.
6 0
2 years ago
An artist used a scale factor of 1 in=8 ft to create a model of a building. if the actual building has a height of 64 feet, how
nalin [4]

Answer:

<em>Okay, so what I think you mean to ask what the scale factor between the model and actual building</em> is, so i crunched the numbers. if 1 in equaled 8 feet and the actual thing was 64 ft, then we can just say that 64 divided by 12 is 5.3, so the model could be

5.3 ft. is the size of the model

BUT

you said how many feet are they apart so in inches its 705, in ft its 58.75

Step-by-step explanation:

a foot is 12 in.

64/12 is 5.3

64 ft is 768 inches, and 5.3 is 63.

768-63 = 705.

there are 705 inches in difference, in feet its 58.75

8 0
2 years ago
What is the value of the expression i0•i1•i2•i3•i4
My name is Ann [436]

\bf \stackrel{1}{i^0}\cdot \stackrel{i}{i^1}\cdot \stackrel{-1}{i^2}\cdot \stackrel{-i}{i^3}\cdot \stackrel{1}{i^4}\implies i\cdot i\cdot 1\implies i^2\implies -1

8 0
3 years ago
Read 2 more answers
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