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3 years ago

14

Tickets to a science Museum cost $19.95 each there is a three dollar charge for each order no matter how many tickets are ordere

d right and equation for each course and dollar of ordering tickets then find The total cost if you order five tickets

1 answer:

denis23 [38]3 years ago

8 0

If the three dollars isn't charged onto each ticket the answer should be $102.75

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The product of eight and a number Q is at least 32

Dennis_Churaev [7]

" the product " means multiply

the product of 8 and a number Q is at least 32...

8Q > = 32 (thats greater then or equal to)

3 0

4 years ago

Read 2 more answers

Luke has $21 more than rachel and $48 more than daniel. altogether they have $168. how much does luke have?

Anettt [7]

this can be solve by 3 variable equation

let x be the money of luke

y money of rachel

z money of daniel

first equation

x = y + 21

second equation

x = z + 48

third equation

x + y + z = 168

solving simultaneously

x =79

y = 58

z = 31

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7 0

3 years ago

What is the percent of increase from 45 to 70?21.7%35.7%55.6%64.3%

SSSSS [86.1K]

Answer:55.6%

Step-by-step explanation:

45-70= -25

-25/45 = 0.555

=55.6

4 0

3 years ago

3x + 3y =15 and x = -3y -1

saul85 [17]

Answer:

(x, y) = (8, -3)

Step-by-step explanation:

You can substitute for x in the first equation:

3(-3y -1) +3y = 15

-6y = 18 . . . . . add 3 and simplify

y = -3 . . . . . . . divide by -6

x = -3(-3) -1 = 8 . . . . find x using the second equation

The solution to this system of equations is (x, y) = (8, -3).

4 0

3 years ago

Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)

zubka84 [21]

$\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 
$

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

$\frac{ \sqrt{-49}}{7-2i-4-9i}$

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result:

$\frac{ \sqrt{-49} }{3-11i}$

Now, the $\sqrt{-49}$ must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to $\sqrt{49} \sqrt{-1}$
This means that we get the result 7i for the numerator.

$\frac{7i}{3-11i}$

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: $x^2 - y^2 =(x+y)(x-y)$
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

$\frac{7i (3+11i)}{(3-11i)(3+11i)}$

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how $(3-11i)(3+11i)= 3^2 -(11i)^2$ therefore, we can finally write:

$\frac{7i(3+11i)}{3^2 - (11i)^2 }$

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product $7i(3+11i) = 21i+77i^2$ .
You should know from your classes that i^2 = -1, thefore the numerator simplifies to $-77+21i$
You can do it as a curious thing, but simplifying yields the result:
$\frac{-77+21i}{130}$

7 0

3 years ago