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topjm [15]
3 years ago
11

The ratio of number of male and female teachers in a school is 3:4. Find the number of male teachers if there are 16 female teac

hers​
Mathematics
2 answers:
nataly862011 [7]3 years ago
7 0

Answer:

12 male teachers.

Step-by-step explanation:

if there is 16 females and the ratio is 3:4 it would be 12 due to 4 times 4 being 16. Meaning that i would do 3 times 4 which would result in having 12 male teachers.

Alex_Xolod [135]3 years ago
6 0

Answer:

12 male teachers

Step-by-step explanation:

If the ratio is 3:4, and the number of female teachers is 16, then the number of male teachers must be 12. This can be confirmed by multiplying both 3 and 4 by 4, or 12/16 = 3/4.

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What is the greatest common factor of 42, 56, and 112
VashaNatasha [74]

Answer: gcf, hcf, gcd (42; 112) = 14 = 2 × 7: greatest (highest) common factor (divisor), calculated.

Step-by-step explanation:

8 0
3 years ago
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Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
4 years ago
Find the balance in the account. $2,500 principal earning 4%, compounded quarterly, after 4 years
Rus_ich [418]
Formula:
A(t)=P(1+(r/n))^)nt)

A(4)=2500(1+(0.04/4))^(4*4)
A(4) = 2500(1.01)^16
A(4) = 2500*1.1726
<span>A(4) = $2931.45</span>
6 0
3 years ago
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The population of a town is 14,000 and is decreasing at a rate of 1.5% each year. Write an exponential decay equation to find th
sergejj [24]

Answer: the population after 10 years is 12036

Step-by-step explanation:

We would apply the formula for exponential growth which is expressed as

A = P(1 - r)^ t

Where

A represents the population after t years.

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 14000

r = 1.5% = 1.5/100 = 0.015

t = 10 years

Therefore, the exponential decay equation to find the population of the town after 10 years is

A = 14000(1 - 0.015)^10

A = 14000(0.985)^10

A = 12036

8 0
3 years ago
Can you answer the question in the picture pls :)
Sergeu [11.5K]
The answer is letter B
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3 years ago
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