Answer:
what is the question??
Step-by-step explanation:
I'm reading this as

with

.
The value of the integral will be independent of the path if we can find a function

that satisfies the gradient equation above.
You have

Integrate

with respect to

. You get


Differentiate with respect to

. You get
![\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%20f%7D%7B%5Cpartial%20y%7D%3D%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20y%7D%5Bx%5E2e%5E%7B-y%7D%2Bg%28y%29%5D)


Integrate both sides with respect to

to arrive at



So you have

The gradient is continuous for all

, so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is
Answer:
area of the merry go round =πr²
=22/7×3²
=28.28
answer is option D
1) he is not reasonable because pounds per feet would mean you would do 7.3/14.6 which is a decimal
hope this helped :)
Answer:
x= -10
Step-by-step explanation:
The equation is y2-y1 over x2 over x1 so
1-(-2) over -9-(x)=3
1+2=3 over -9-(x)
3/-9-x times -9-x = 3 times -9-x
3=3(-9-x)
3=-27-3x
3+27=-3x
30= -3x
-10= 3x
hope it helps man!!! :)
ps may i have brainliest so i can level up