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yuradex [85]
3 years ago
13

Kara did a survey to determine to study the types of pets that students in her school had. She surveyed 300 students and found t

hat 40% of them had cats, 12% had both cats and dogs, and 45%
didn't have either. How many of the students that Kara surveyed had dogs?
1) 61
2) 71
3) 81
4) 91​
Mathematics
1 answer:
julsineya [31]3 years ago
3 0

Answer:

(C)81

Step-by-step explanation:

Total Number of Students =300

Percentage who had cats, n(C) = 40%

Percentage who had both cats and dogs , n(C \cap D) = 12%

Percentage who had neither cats nor dogs, n(C \cup D)' =45%

Now:

Universal Set, U = n(C)+n(D)-n(C \cap D)+n(C \cup D)'

100 = 40 + n(D)-12+45\\n(D)=100-73\\$Percentage of those who own dogs =27\%

Therefore:

Number of Students who had dogs

=27% of 300

=81

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Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact
umka2103 [35]

Solution:

The permutation formula is expressed as

\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

Thus,

Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

Hence, there are 28 combinations and 20160 permutations.

7 0
1 year ago
Which is a parallelogram with four congruent sides whose diagonals bisect each other and intersect at four right angles?
Charra [1.4K]

Answer:

I believe that the answer is B. Rhombus.

Step-by-step explanation:

A rhombus has the properties of a parallelogram and the diagonals intersect at right angles.

Hope this helps!

3 0
3 years ago
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Shira has 20 books on her bookshelf. Of those 15 are about horses, the rest are nature books. What fraction of Shiras books are
givi [52]

Answer:

1/4

Step-by-step explanation:

15 out of the 20 books are horses. 5 of those are nature. 5/20 is the fraction, but can be simplified to 1/4

6 0
3 years ago
Every possible cross section of a three-dimensional figure is a circle. What is the figure?
dsp73
A cross section is the shape we get when cutting straight through an object. In geometry it is the shape made when a solid is cut through by a plane. cylinder cross section.The cross section of this circular cylinder is a circle.
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15 POINTS!<br> What is the correct answer for Dean's problem? Explain where he went wrong.
prohojiy [21]

Answer:

The slope is 5/-2.

Step-by-step explanation:

Slope is y1-y2 over m1-m2 (rise over run). The first ordered pair is -2 (m1) and 11 (y1). We then subtract the second ordered pair (4 (m2) and -4 (y2)) from the first.

11 - (-4) = 11 + 4 = 15

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Remember, slope is rise over run (y over x), so the slope is 15/-6. Now, we must simplify. 15/-6 = 5/-2

Dean went wrong because he thought that slope was run over rise (x over y). If he had switched the two numbers, his answer would have been correct.

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