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2 years ago

Please help asap! thank you

Mathematics

2 answers:

nasty-shy [4]2 years ago

6 0

The HTTP 404, 404 Not Found, 404, 404 Error, Page Not Found, File Not Found, or Server Not Found

ololo11 [35]2 years ago

3 0

Answer:

w = ( 6x^5 - 18x^4 - 30x^3 + 28x^2 - 26x + 40 ) / ( x-4 )

Step-by-step explanation:

A = L x W

A = 6x^5 - 18x^4 - 30x^3 + 28x^2 - 26x + 40

L = ( x-4 )

W = A / L

W = ( 6x^5 - 18x^4 - 30x^3 + 28x^2 - 26x + 40 ) / ( x-4 )

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15+0.5x=25+0.25x please show how

sveticcg [70]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

x= 40

8 0

2 years ago

Read 2 more answers

Log based question, i just need help with parts b and c

Tanya [424]

Answer:

b) There is translation 3 units to the right and 1 unit up

c) The domain is {x I x > 3}

The equation of the asymptote is x = 3

Step-by-step explanation:

* Lets revise the rule of the translation

- If the function f(x) translated horizontally to the right

by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left

by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up

by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down

by k units, then the new function g(x) = f(x) – k

* Now lets solve the problem

b) ∵ f(x) = $log_{2} (x-3)+1$

∵ The parent function is $log_{2} x$

∴ x is changed to (x - 3), that means there is a translation 3 units

to the right

∵ We add the parent function by 1, that means there is a translation

1 unit up

* There is translation 3 units to the right and 1 unit up

c) To find the domain of the function, find the values of x which

make the function undefined

∵ $log_{2}(0)$ is undefined

∴ x - 3 can not be 0

∵ x - 3 = 0 ⇒ add 3 to both sides

∴ x = 3

∴ The domain of the function is all real number greater than 3

* The domain is {x I x > 3}

∵ x can not be 3

∴ There is a vertical asymptote, its equation is x = 3

* The equation of the asymptote is x = 3

# Look to the attached graph for more understand for the domain

and the equation of the asymptote

4 0

3 years ago

What are the vertical asymptotes of the function f(x) = 2x + 8 / x2 + 5x + 6?

Irina18 [472]

I'm assuming the function is f(x) = (2x+8)/(x^2+5x+6). If so, make sure to use parenthesis to indicate that you're dividing all of "2x+8" over all of "x^2+5x+6" as one big fraction. Otherwise, things are ambiguous and it leads to confusion.

Side Note: x^2 means "x squared"

Factor the numerator: 2x+8 = 2(x+4)
Factor the denominator: x^2+5x+6 = (x+2)(x+3)

There are no common factors between the numerator and denominator. So there is nothing to cancel out.

Recall that you cannot divide by zero. Something like 1/0 is undefined.
We need to find the x values that cause the denominator to be zero.
Set the denominator equal to zero and solve for x
x^2+5x+6 = 0
(x+2)(x+3) = 0
x+2 = 0 or x+3 = 0
x = -2 or x = -3

The x values x = -2 or x = -3 will lead to the denominator being zero. This means that the vertical asymptotes are x = -2 or x = -3 as shown by the blue dashed vertical lines in the attached image.