Question

A ladybug and ant move at constant speeds. The diagrams with tick marks show their positions at different times. Each tick mark represents 1 centimeter.
In your textbook pg. 111, scale the vertical and horizontal axes by labeling each grid line with a number. You will need to use the time and distance information in the tick-mark diagrams.

Which line shows the ladybugs movement? The ant?
Unit rate for the Ladybug? The ant?
How long does it take for the ladybug to travel 12 cm? The ant?

Answer 1

Answer:

From the graph we can say that ant is moving faster than the ladybug

Slope of the ant's movement will be steeper than the ladybug

• Hence, line "v" denotes the speed of ant and line "u" denotes the speed of ladybug.

Unit rate/slope of the graph is (distance traveled/elapsed time)

• Unit rate of ant is 3/2 cm/sec and that of ladybug is 1 cm/sec.
• Ant takes (12×2/3) = 8 sec and ladybug takes (12×1) = 12 sec to travel 12 cm.

Remember ant will take less time to travel a certain distance than ladybug.