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qwelly [4]
3 years ago
9

Find the Area of the figure below, composed of a parallelogram and one semicircle. Rounded to the nearest tenths place

Mathematics
2 answers:
mart [117]3 years ago
5 0

Step-by-step explanation:

Area of Figure

= Area of Parallelogram + Area of Semicircle

= (26)(13) + 0.5π(24/2)²

= 338 + 72π

= 564.2.

kifflom [539]3 years ago
3 0

Answer:

Area of the figure :---

Area of the parallelogram+area of the semicircle

(26×13)+(1/2)π(12)²

=338+72π

=338+226.2

=564.2 square unit

<h3><u>564.2 square unit</u> is the right answer.</h3>
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Find the midpoint M of the line segment joining the points S = (1, -2) and T = (-7,-6).​
mafiozo [28]

Answer:

(-3 ,-4)

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You’re trying to find the better buy so you want to find out how much you’re paying per unit (in this case kg)

So you divide the price by the unit (kg)

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8 0
2 years ago
What is the solution to the equation below? Round your answer to two decimal places. 3e2x + 12 = 42
Shkiper50 [21]

Answer:

X= 5.52

Step-by-step explanation:

1. Solve the equation:

e×2x + 12= 42

x=15/e

2. Round x=15/e to the required place

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5 0
1 year ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!! Can U Answer All These.
mash [69]

<u>QUESTION 1</u>

In figure A, the area of the bigger square is 625\:units^2. This means that the length of this square is the hypotenuse of the right angle triangle formed, which is 25\:units.

The area of the two smaller squares are 576\:units^2 and 49\:units^2.


The length of these two squares form the two shorter legs of the right angle triangle, which are 24 and 7 units respectively.


Therefore we can write the equation, 576+49=625.


This implies that, 24^2+7^2=25^2


We can see that the sum of the squares of the two shorter legs equals the square of the longer side which is the hypotenuse and this what the Pythagoras theorem says.


But in fig. B,

5^2+4^2\ne 6^2


Therefore the correct answer is Fig A.


<u>QUESTION 2</u>

See diagram.

We introduce the two lines as shown in the diagram.

From Pythagoras' Theorem,

|AB|^2=|AC|^2+|BC|^2


But |AC|=|7-3|=4 units.


and

|BC|=|8-2|=6 units.

This implies that,

|AB|^2=4^2+6^2


|AB|^2=16+36


|AB|^2=52


|AB|=\sqrt{52}


|AB|=2\sqrt{13}


|AB|=7.2 to the nearest tenth.



<u>QUESTION 3</u>

The numbers 3,4 and 5 form a Pythagorean triplet because 3^2+4^2=5^2.


If these numbers represent the side lengths of a triangular fence, then the triangular fence must be a right angle triangle.

The correct answer is B

Yes,because  3^2+4^2=5^2.


<u>QUESTION 4</u>

See graph.

We want to find the image of the triangle with vertices A(-5,-4), B(-2,-4), and C(-5,-1) after a reflection in the x-axis.

The mapping for this transformation is

P(x,y)\rightarrow P'(x,-y).


We just have to negate the y-coordinates.

A(-4,-5)\rightarrow A'(-4,5).


B(-4,-1)\rightarrow B'(-4,1).


C(-5,-1)\rightarrow C'(-5,1).








3 0
3 years ago
What is 332,409 written in word form?
Diano4ka-milaya [45]

three hundred thirty-two thousand, four hundred nine.

:)

4 0
3 years ago
Read 2 more answers
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