Second one ...... i hope it’s right
Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
1/4 < 5/4
Step-by-step explanation:
Since the numbers have the same denominator, we compare the numerators
1<5
so 1/4 < 5/4
Answer:
36
Step-by-step explanation:
Think of the unknown sized side as a half of 12 and multiply them together when your triangle is obtuse like that. and split the answer from 6 times 12.
I hope this helped you!
