8+2=10!!!!!!!!!!!!!!!!!!!!!!
Question:
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank
Answer:
The percent Decrease of water in the tank is 50%
Step-by-step explanation:
Given:
Initial amount of water in the tank at the noon = 6 cm
amount of water remained in water after several hours = 3 cm
To Find:
The percent decrease =?
Solution:
The percent decrease in the tank
=>
Substituting the values
=>
=>
=>
=> 50
-2(x - 3) = 5(2x + 3)
-2x + 6 = 10x + 15
6 = 10x + 15 + 2
6 = 12x + 15
6 - 15 = 12x
-9 = 12x
-9/12 = x
-3/4 = x or in decimal form; -0.75
hope this helps, God bless!
-2 5/12 - 3 2/3 + 1 1/2 =
- 29/12 - 11/3 + 3/2 =
-29/12 - 44/12 + 18/12 =
-73/12 + 18/12 =
- 55/12 or - 4 7/12 <===