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2 years ago

7

Help please!! Branniest answer will be given!

1 answer:

Levart [38]2 years ago

6 0

Answer:

30

Step-by-step explanation:

area of triangle 1/2 b×h

1/2 10×6=30m^×

Mark me brainliestt

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Find the slope (-2,-4) (-5,5)

diamong [38]

Answer:

Your answer would be Slope m = -3

Step-by-step explanation:

Step 1: Graph the points on a <u>coordinate plane</u>( <em>refer to image!)</em>

Whenever your trying to find a slope of 2 order pairs, remember this

m = rise/run. ( Slope = rise over run.) = Δy/Δx

Now we solve:

M = rise/run = Δy/Δx

M = y2 - y1/x2-x1

M = 5 - (-4) / -5-(-2)

<u>So we get M = 9/-3 and </u><u>9 divided by -3 is -3 </u>

<u />

So, the slope of (-2,-4) and (-5,5) is -3.

5 0

2 years ago

Help please i have 0 clue on what to do

zheka24 [161]

Answer:

Step-by-step explanation:

$9x6x12$ = 648 the length(12m), width(6m), and height(9m) that all i can give you for now because this got me losing brain sells

5 0

3 years ago

Read 2 more answers

Hi<br><br> what is 9257289357218q4918 x 5823829.94325892580254

lana [24]

Answer:

ridiculous

Step-by-step explanation:

tssssk *extra characters*

3 0

3 years ago

Read 2 more answers

An equations'system

yaroslaw [1]

$1. \: x = \frac{11}{9} y + \frac{5}{9} \\ x = \frac{5}{6} y + \frac{1}{6} \\ \\ 2. \: x = \frac{3}{2} y + 2 \\ x = \frac{3}{2} y + 2$

3 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago