To solve this problem, what we have to do is to calculate
for the z scores of each condition then find the probability using the standard
normal probability tables for z.
The formula for z score is:
z = (x – u) / s
where,
x = sample value
u = sample mean = 23 days
s = standard deviation = 1 day
A. P when x < 21 days
z = (21 – 23) / 1
z = -2
Using the table,
P = 0.0228
Therefore there is a 2.28% probability that the hatching
period is less than 21 days.
B. P when 23 ≥ x ≥ 22
<span>z (x=22) = (22 – 23) / 1 = -1</span>
P (z=-1) = 0.1587
z (x=23) = (23 – 23) / 1 = 0
P (z=0) = 0.5
P = 0.5 - 0.1587 = 0.3413
Therefore there is a 34.13% probability that the hatching
period is between 22 and 23 days.
C. P when x > 25
z = (25 – 23) / 1
z = 2
P = 0.9772
This is not yet the answer since this probability refers
to the left of z. Therefore the correct probability is:
P true = 1 – 0.9772
P true = 0.0228
<span>Therefore there is a 2.28% probability that the hatching
period is more than 25 days.</span>
Answer:
Step-by-step explanation:
I would not agree with Mai because 1km equals one thousand meters and soccer fields in general are 90 to 120 meters long and 45 to 90 meters wide so it impossible that she could have walked 1km even if she walked around it twice
I really don't even know this this app literally
only gives you like 2 answers at a time.
Answer:
Usually it's in standard form: ax²+bx+c
or vertex form: y=a(x-h)²+k
If you put the graph into a graphing calculator it's going to look like a hill/depression.
Step-by-step explanation:
Standard form ex: 3x²+2x+1
Vertex form ex: y=4(x-1)²-2
