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serg [7]
3 years ago
11

1.309 > 1.315 lololoolollooolllllllllllllllllllll

Mathematics
2 answers:
kvv77 [185]3 years ago
6 0

Answer:

I’m confused on what you want me to do but that is false

Step-by-step explanation:

Lady bird [3.3K]3 years ago
6 0

Answer:

the answer is 1.309<1315

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a scaled drawing of a rectangular park is 5 inches wide and 7 inches long. the actual park is 210 yards long. what is the width
VMariaS [17]

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I think the width would be 150 yd

Step-by-step explanation:

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Find the following measure for this figure.
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  • l=11
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Now

LSA:-

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4 0
2 years ago
Glenn, the owner of a hardware store, originally paid $54.60 for 15 tool sets. At his year-end clearance sale, he sold the last
Sonja [21]

The amount of money he lose on the last tool set is: $30.60.

<h3>Amount lose</h3>

Using this formula

Amount lose=Original amount paid -Selling price

Where:

Original amount paid=$54.60

Selling price=$24.00

Let plug in the formula

Amount lose=$54.60-$24.00

Amount lose=$30.60

Therefore the amount of money he lose on the last tool set is: $30.60.

Learn more about amount lose here:brainly.com/question/11872053

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3 0
2 years ago
Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___
devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 cm^2

and specific resistance (ρ) = 1.8 \times 10^{-6} ohm-cm.

Use the formula  R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, R=\frac{1.8 \times 10^{-6} \times 270}{0.030} ohm

Simplify:

R = 0.0162 ohm = 1.62\times 10^{-2} ohm

Therefore, the resistance of copper wire is,  1.62\times 10^{-2} Ω


8 0
3 years ago
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