Part 1) area of triangle=b*h/2 b=2.9 cm h=9 cm so area=2.9*9/2-----> 13.05 cm²
the answer part 1) is 13.05 cm²
Part 2) area of the figure=area of rectangle+area of triangle
find the area of rectangle area rectangle=b*h b=12 ft h=? tan 45=1 tan 45=h/(22-10)----------> h/10=1-------> h=10 ft area of rectangle=12*10-----> 120 ft²
area of triangle=b*h/2 b=10 ft h=10 ft area of triangle=10*10/2----> 50 ft²
area of the figure=120+50----> 170 ft²
the answer Part 2) is 170 ft²
Part 3) <span>the area of kite is half the product of the diagonals. </span>Area=(d1*d2)/2 d1=5+5---> 10 ft d2=16+8----> 24 ft area=(10*24)/2----> 120 ft²
the answer Part 3) is 120 ft²
Part 4) the area of rhombus is half the product of the diagonals. Area=(d1*d2)/2 d1=6+6---> 12 m d2=6+6----> 12 m area=(12*12)/2----> 72 m²
the answer part 4) is 72 m²
Part 5)
area of the figure=6*area of one triangle
area of triangle=b*h/2 b=4 cm is an equilateral triangle applying the Pythagoras theorem h²=4²-2²-----> h²=12-----> h=2√3 cm
