A bus traveling at 50mph how long will it take for the bus to travele at 80mph

Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years Rs.1290 as interest Compound

Natalija [7]

Given info:

Compound Interest = Rs.1290

Rate of Interest = 15% p.a

Time = 2 years

<h3>Formula we have to know:-</h3>

$\dag{\underline{\boxed{\sf{C.I = P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1}}}}$

<u>Where</u>

C.I = Compound Interest

P = Principle

R = Rate of Interest

N = Time

$\textsf{ \underline{Solution-}}\\$

Here

C.I = Rs.1290

R = 15%

N = 2 years

Principle = ?

Now,Calculating the sum (Principle) borrowed by Rachna

$\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}$

Substituting the given values

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}$

$\quad{: \implies{\sf{1290 = P \times {0.3225}}}}$

$\quad{: \implies{\sf{\dfrac{1290}{0.3225} = P}}}$

$\quad{: \implies{\sf{\dfrac{1290 \times 1000}{0.3225 \times 1000} = P}}}$

$\quad{: \implies{\sf{\dfrac{12900000}{3225} = P}}}$

$\quad{: \implies{\sf{\cancel{\dfrac{12900000}{3225}} = P}}}$

$\quad{: \implies{\sf{Rs.4000 = P}}}$

$\quad{\dag{\underline{\boxed{\tt{\blue{Principle} = \purple{Rs.4000 }}}}}}$

$\begin{gathered}\end{gathered}$

<u>Hence,</u>

The sum (Principle) is Rs.4000.

3 0

3 years ago

Sara makes a cuboid having sides 15cm and 30cm .how many such cuboids will be needed to form a cube

zhuklara [117]

cuboid=3*3*5 [i.e l*b*h]

LCM of 3,5=15

i.e 15cm is the dimension of the final cube.

therefore cuboid required across length=15/3=5

similarly, across breadth=15/3=5

similarly, across height=15/5=3

Therefore total no of cuboid=5*5*3=75

4 0

4 years ago

Suppose you want to have $400,000 for retirement in 30 years. Your account earns 4% interest.

Ne4ueva [31]

Answer:

if he wants to have $400000 on gis bank in 30 years at 4 %rate then he needs to deposit $15151.5 per month

5 0

4 years ago

What’s the area and perimeter for this problem?

neonofarm [45]

Answer:

area:1.9×0.75÷2

perimeter:2+0.75+2.25

5 0

2 years ago

Pls help asap ily

STatiana [176]

Answer:

2 hours

Step-by-step explanation:

you can write two linear equations and then set them equal to each other to see when they intersect. so for the first equation which will be representing the junior space cadets distance from his house. this can be written as

d = 50t + 50

where t represents time and d represents distance. there is 50 being added to the equation since he had already been traveling for an hour

the second equation which will represent his sister Gwen can be represented as

d = 75t

Now we set them equal to each other

50t + 50 = 75t

50 = 25t

2 = t

3 0

2 years ago