Answer:
Explanation:
Given
capacitance
Resistance
Applied Voltage
Charge on Capacitor in a R-C circuit is given by
A person in a laboratory is asked to taste and describe her conscious experience of two different drinks. The person talks about
1 answer:
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The question is incomplete. Here is the complete question.
Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.65T.
part (a): What is the potential difference, in volts, required in the first part of the experiment to accelerate electrons to a speed of 6.2 x 10⁷m/s?
part (b): Find the radius of curvature, in meters, of the path of a proton accelerated trhough this same potential after the proton crosses into the region with the magnetic field.
part (c) what is the ratio of the radii of curvature for a proton and an electron traveling through this apparatus?
Answer: (a) V = - 109.44 x 10² V
(b) 9.95 x 10⁻¹ m
(c) ratio = 1800
Explanation: (a) <u>Potential</u> <u>difference</u> is defined as the energy a charged particle has between two points in a circuit. It is calculated as
where
pe is potential energy
q is charge
and its unit is joule/coulomb of Volts (V).
To determine potential difference required to accelerate a particle, we have to use the principle that the total energy of a system is conserved and one transforms into the other.
In this case, potential energy is transformed in kinetic energy:
pe = V.q
ke =
so
Calculating:
V = x 10²V
Potential difference of an electron to have speed of 6.2x10⁷m/s is x 10²V.
(b) A particle has a circular motion when there is a magnetic force acting on it.
Velocity and magnetic force are always perpendicular to each other. Because of that, there is no work on the particle and so, kinetic energy and speed are constant. Since magnetic force supplies centripetal force:
The radius of the curvature, for a proton, will be:
r = 9.95 x 10⁻¹m
The raius of curvature, when it is a proton, is 0.995m.
(c) Radius of curvature, if it was a electron:
r = 54.33 x 10⁻⁵m
ratio =
ratio = 1800
Ratio of radii of curvature is 1800, meaning curvature created when it is a proton is 1800 times bigger than when it is a electron.
Answer:
2465 J/g
Explanation:
The amount of energy required to boil a sample of water already at boiling point is given by
where
m is the mass of the water sample
is the specific latent heat of vaporization of water
In this problem, we know
Solving the equation for , we find