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Dmitry [639]
3 years ago
7

Frictional force is____of area of contact​

Physics
1 answer:
Elis [28]3 years ago
8 0

Answer:

The force due to friction is generally independent of the contact area between the two surfaces. This means that even if you have two heavy objects of the same mass, where one is half as long and twice as high as the other one, they still experience the same frictional force when you drag them over the ground.

Explanation:

Independent

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Please...physics rotation questions
kari74 [83]
1st Question:
There are 4 formulas involving angular velocity:
For the first question, we are given the initial angular velocity (ωo), final angular velocity (ωf), and the amount of time. The question is asking us to find the angular acceleration (α).
Knowing this information, we can use w=wo+ \alpha t
Lets plug in the values given in the question:
w=wo+ \alpha t
123  \frac{rad}{sec}  = 11  \frac{rad}{sec} + (4.5 sec) \alpha
Now we just solve for \alpha
123 \frac{rad}{sec} = 11 \frac{rad}{sec} + (4.5 sec) \alpha
Subtract 11 from each side
112 \frac{rad}{sec} = (4.5 sec) \alpha
Divide each side by 4.5 sec. 
\alpha = 24.89  \frac{rad}{sec^{2} }
----------------------------------------------------------
2nd Question:
For the second question, we want to find the change in distance (which is AKA radians). So we know we would need to use either the 1st, 3rd or the 4th equation. We are given time (t=45 s), the initial velocity (wo=0 rad/s), and the final velocity (w=245 rad/s). Since the 4th equation doesn't have time, and the 3rd equation has angular acceleration (which we weren't given), we know we will need to use the 1st equation. 
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7 0
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Explanation:

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6 0
3 years ago
Read 2 more answers
A 5kg box is being pulled for a force of 20 n and is sliding with an acceleration of 2 m/s. Find the coefficient of friction
RUDIKE [14]

Answer:

Coefficient of friction = 0.5

Explanation:

Given:

Mass of box = 5 kg

Force applied = 20 N

Acceleration = 2 m/s²

Find:

Coefficient of friction

Computation:

Friction force = Mass x Acceleration.

Friction force =  5 x 2

Friction force = 10 N

Coefficient of friction = Friction force / Force applied

Coefficient of friction = 10 / 20

Coefficient of friction = 0.5

3 0
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nikklg [1K]
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