well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.
![\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbf%20%7C2x-5%7C%3D4%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%282x-5%29%3D4%5Cimplies%202x%3D9%5Cimplies%20x%3D%5Ccfrac%7B9%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20-%282x-5%29%3D4%5Cimplies%202x-5%3D-4%5C%5C%5B1em%5D%202x%3D1%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B2%7D%20%5Cend%7Bcases%7D%20)
Answer:
Volume of cone = 418.67 cm³ (Approx.)
Step-by-step explanation:
Given:
Radius of cone = 5 cm
Height of cone = 16 cm
Find:
Volume of cone
Computation:
Volume of cone = [1/3][π][r²][h]
Volume of cone = [1/3][3.14][5²][16]
Volume of cone = [1/3][3.14][25][16]
Volume of cone = [1/3][3.14][400]
Volume of cone = [1/3][1,256]
Volume of cone = 418.67 cm³ (Approx.)
Answer:
h= -8/3
Picture Explanation:
- Divide 3 on both sides of the equal sign, as shown above, so (h) can be alone.
- Since negative 8, let alone positive 8, can't be divided into 3, you simply leave the fraction as is. So you're left with (h= -8/3)
<em><u>Hope this makes sense.</u></em>