It's B
Slope is negative, the other must be positive due to m1 x m2 = - 1
m1 = -2/5
The diagram shows a gradient of -2/5. So, the
reciprocal of this valve to make - 1 is 5/2 (which is the - 2/5 flipped upside down, but positive)
-2/5 x 5/2 = - 10/10 (or - 1)
Thus, the perpendicular line to this has a gradient of 5/2.
Hope this helps!
Answer:
The answer to your question is below
Step-by-step explanation:
Data
Center = (0, 0)
Vertex = (13, 0)
Focus = (12, 0)
Process
From the data we know that it is a horizontal ellipse.
1.- Calculate "a", the distance from the center to the vertex.
a = 13
2.- Calculate "c", the distance from the center to the focus
c = 12
3.- Calculate b
Use the Pythagorean theorem to find it
a² = b² + c²
-Solve for b
b² = a² - c²
-Substitution
b² = 13² - 12²
-Simplification
b² = 169 - 144
b² = 25
b = 5
4.- Find the equation of the ellipse
or 
Given:
bisects ∠RST.

To find:
The
.
Solution:
Since,
bisects ∠RST, therefore
...(1)
Now,

[Using (1)]

![[\text{Given }m\angle RSV=64^\circ]](https://tex.z-dn.net/?f=%5B%5Ctext%7BGiven%20%7Dm%5Cangle%20RSV%3D64%5E%5Ccirc%5D)

Therefore, the value of
is
.
24+14 = 3a + 4a +2a
38 = 9a
——————————
Hope it is helpful.