If AB≅DE, BC = EF, and ∠ACB ≅ ∠DFE, then ΔABC ≅ ΔDEF.
2 answers:
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The vertex form needed is :
Given the equation:
The vertex form of is given by:
Here, (h,k) is the vertex of the parabola equation given.
Conversion will go like this:
This is the resultant vertex form.
Thus the vertex form needed is :
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Answer:
See below
Step-by-step explanation:
(a) Field lines
A negatively charged particle has an electric field associated with it.
The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.
Opposite charges attract, so the field lines point toward the centre of the particle.
For an isolated negative particle, the field lines would look like those in Figure 1 below.
If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.
A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.
We can make a similar statement about appositive charge approaching from the left.
Thus, there are few field lines in the region between the two particles.
(b) Coulomb's Law
The formula for Coulomb's law is
F = (kq₁q₂)/r²
It shows that the force varies inversely as the square of the distance between the charges.
Thus, the force between the charges decreases rapidly as they move further apart.
Answer:
Step-by-step explanation:
Combine like terms. 1/4 and 7/8 are like terms and LCD of 4 and 8 is 8
9/10y and -3/5y are like terms and LCD of 10 , 5 is 10