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IrinaVladis [17]
3 years ago
13

If AB≅DE, BC = EF, and ∠ACB ≅ ∠DFE, then ΔABC ≅ ΔDEF.

Mathematics
2 answers:
Ede4ka [16]3 years ago
3 0

Answer:

false

Step-by-step explanation:

melisa1 [442]3 years ago
3 0

Answer:

false

Step-by-step explanation:

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Write the equation of the line perpendicular to y= 2/5x+6/6 that passes through the point (-2,6)
Oliga [24]
The line to find: y = mx + b
the line perpendicular to y= 2/5x+6/6 so it has the slope m × 2/5 = -1
thus the slope m = -5/2
the line passes through the point (-2,6) so:
6 = (-5/2)×(-2) + b so b = 1


the equation of the line is y = -5/2x +1
3 0
3 years ago
Which of the following is the graph of y = 5?
Annette [7]
Slope: 0
Y-intercept: 5
The answer is 0,5
I hope this helps.
8 0
3 years ago
Solve for x in the equation x^2+14x+17=-96
Goshia [24]
X²+14x+49+17=-96+49
(x+7)²=-64, x+7=±8i, x=-7±8i, so x=-7+8i or -7-8i.
5 0
3 years ago
Read 2 more answers
Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

4 0
3 years ago
Read 2 more answers
Help pleaseeeeeeeeeeeeee
Vlada [557]


Here is answer in the picture I hope this will help to you

3 0
2 years ago
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