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Andrej [43]
3 years ago
6

-4y^5 + 6y^3 + 8y^2 - 2y

Mathematics
1 answer:
vitfil [10]3 years ago
8 0
The answer is -2y•(2y^4 - 3y^2 - 4y + 1)
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Given that f(x) = x^2? + 9x + 18 and g(x) = x + 3, find (f ÷ g) (x) and express the result in standard form.​
lawyer [7]

Answer:

x + 6

Step-by-step explanation:

(f ÷ g)(x)

= \frac{x^2+9x+18}{x+3} factorise the numerator

= \frac{(x+3)(x+6)}{x+3} ← cancel the factor (x + 3) on numerator/ denominator

= x + 6

5 0
3 years ago
mei has eight jars of soup each jar of soup contains 300 milliliters of soup what is the smallest pot mei can use
vichka [17]
300 x 8 = 2400 ml is the smallest pot 
8 0
3 years ago
Bob deposits $5000 into an account that pays simple interest at a rate of 4% per year. How much interest will he be paid in the
Olenka [21]
The answer is 1,200 but all you have to do is figure out what 4% of 5000 is and then multiply that by 6

5 0
3 years ago
On a map, Sanford, NC and Myrtle Beach, SC are 4 inches apart. The distance between cities is actually 156 miles. What scale was
defon

Answer:

39 or 1/39

Step-by-step explanation:

You need to divide these but it depends on how you divide them

  • 4/156=1/39
  • 156/4=39
8 0
3 years ago
suppose a consumer advocacy group would like to conduct a survey to find the proportion p of consumers who bought the newest gen
Zepler [3.9K]

The size of the sample they should take to estimate p with a 2% margin of error and 90% confidence is n = 1691.

In statistics, the margin of error is just the degree of a significant error in the outcomes of random sample surveys.

The formula of margin error is, E = z√((p-vector)(1 - (p-vector)) ÷ n)

E = 2% = 0.02

Confidence level = 90%

Now, the proportion is not given so adopt nominal (p-vector) = 0.05

The critical value at CL of 90% is 1.645.

Thus, making n the subject,

n = z²(((p-vector) × (1 - (p-vector))) ÷ E²)

n = 1.645²((0.5 × 0.5) ÷ 0.02²)

n = 1691.266

n ≈ 1691

Read more about the margin of error at

brainly.com/question/16141482?referrer=searchResults

#SPJ4

4 0
1 year ago
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