Tanya run 50 yards across the diagonal of the rectangular field.
<u>Step-by-step explanation</u>:
Step 1 :
- Length of the rectangular field = 40 yards
- width of the rectangular field = 30 yards
Step 2 :
Measure of the diagonal = √(length^2 + width^2 )
Step 3 :
Diagonal = √(40^2 + 30^2 )
= √(1600 + 900)
= √2500
= ±50
Step 4 :
Since distance cannot be negative, The measure of diagonal = 50 yards.
∴ Tanya runs diagonally across a rectangular field is 50 yards.
The equation for the path of the ball can be measured using a regression model calculator which produced the quadratic model ;
- y(x) = - 16x² + 36x + 4
- Height at x = 1.7 = 18.89 feets
<u>The table given</u> :
Time, x : __0.5 ___ 1 ____ 1.5 ____ 2
Height, y _ 18 ____22 ___ 24 ____ 12
<u>Using </u><u>technology</u><u> such as a </u><u>quadratic regression</u><u> calculator or </u><u>excel</u> ;
The quadratic regression model obtained is :
<u>The </u><u>height after, 1.7 seconds</u><u>, x = 1.7 can be calculated thus</u> :
Put x = 1.7 in the equation :
- y(1.7) = - 16(1.7)² + 36(1.7) + 4
- y = 18.89 feets
Therefore, the height of the baseball after 1.7 seconds will be 18.89 feets.
Learn more : brainly.com/question/22939512
Answer:
The product of the slopes of lines is -1.
i.e. m₁ × m₂ = -1
Thus, the lines are perpendicular.
Step-by-step explanation:
The slope-intercept form of the line equation

where
Given the lines
y = 2/3 x -3 --- Line 1
y = -3/2x +2 --- Line 2
<u>The slope of line 1</u>
y = 2/3 x -3 --- Line 1
By comparing with the slope-intercept form of the line equation
The slope of line 1 is: m₁ = 2/3
<u>The slope of line 2</u>
y = -3/2x +2 --- Line 2
By comparing with the slope-intercept y = mx+b form of the line equation
The slope of line 2 is: m₂ = -3/2
We know that when two lines are perpendicular, the product of their slopes is -1.
Let us check the product of two slopes m₁ and m₂
m₁ × m₂ = (2/3)(-3/2
)
m₁ × m₂ = -1
Thus, the product of the slopes of lines is -1.
i.e. m₁ × m₂ = -1
Thus, the lines are perpendicular.
Answer:
B
Step-by-step explanation:
cus thats the formula