Let us assume that the number of beige tiles bought by Susan = B
Number of red tiles bought by Susan = R
Number of navy-blue tiles bought by Susan =N
Number of tiles bought altogether = 435
Now from the given question we know:
Number of red tiles bought is 25 more than the number of beige tiles.
So
R = 25 + B
Number of navy blue tiles bought is 3 times that of the number of beige tile bought
So
N = 3B
We already know that the total number of tiles bought is 435
Hence
B + R + N = 435
B + (25 + B) + 3B = 435
5B + 25 = 435
5B = 435 -25
5B = 410
B = 82
R = 25 + B
= 25 + 82
= 107
N = 3B
= 3 * 82
= 246
So the number of Beige tiles bought by Susan = 82
The number of red tiles bought by Susan = 107
The number of navy-blue tiles bought by Susan = 246
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The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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