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Anastasy [175]
3 years ago
11

Hello everyone, please help me on this second question (:

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
100 times because it is two places meaning two zeros
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* Any irrelevant answers will be reported as spam* PLEASE HELP!
AnnZ [28]

Answer:

x: the number of minutes spent reading

y: number of pages read

Step-by-step explanation:

339/40= 8.475

y=mx+b

339=40(8.475)+b

339=339+b

0=b

Hope this helps!

8 0
2 years ago
Read 2 more answers
The second derivative of acos(kx) ​
Shkiper50 [21]
F’(x)= -akxsinkx

F’’(x)= -a(kx)^2coskx

I’m really sorry if the answer turned out wrong but I tried my best!
8 0
2 years ago
France Under Louis XVI
enot [183]

Answer:

thx

Step-by-step explanation:

4 0
2 years ago
Chris paid $3,069 for 3 iphones. Each iphone costs the same amount. How much did each iphone cost? Solve this problem using a st
galben [10]

Answer 1029

Step-by-step explanation: So, since all of the phones cost 3,069 in total, divide 3,069 by three. You get 1029.

7 0
2 years ago
The petronas towers in Kuala Lumpur, Malaysia, are 452 meters tall. A woman who is 1.75 meters tall stands 120 meters from the b
bazaltina [42]

Answer:

75.1^{\circ}

Step-by-step explanation:

In this problem, we have:

H = 452 m is the height of the Petronas tower

h = 1.75 m is the height of the woman

d = 120 m is the distance between the woman and the base of the tower

First of all, we notice that we want to find the angle of elevation between the woman's hat the top of the tower; this means that we have consider the difference between the height of the tower and the height of the woman, so

H' = H-h = 452-1.75=450.25 m

Now we notice that d and H' are the two sides of a right triangle, in which the angle of elevation is \theta. Therefore, we can write the following relationship:

tan \theta = \frac{H'}{d}

since

H' represents the side of the triangle opposite to \theta

d represents the side of the triangle adjacent to \theta

Solving the equation for \theta, we find the angle of elevation:

\theta = tan^{-1}(\frac{H'}{d})=tan^{-1}(\frac{450.25}{120})=75.1^{\circ}

3 0
3 years ago
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