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3 years ago

If someone could help!

Mathematics

1 answer:

ad-work [718]3 years ago

4 0

Step-by-step explanation:

This time round, use SOH method (Sin angle = Opposite/Hypotenuse)

given Opposite = 7

Hypotenuse = 10

$\sin(x) = \frac{opposite}{hypotenuse} \\ \sin(x) = \frac{7}{10} \\ x = {sin}^{ - 1} ( \frac{7}{10} ) \\ = 44.4deg(nearest \: tenth)$

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Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste

lisabon 2012 [21]

Answer:

(a) The value of x is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

Step-by-step explanation:

Denote the events as follows:

R = reported case of rabies is a raccoon

F = reported case of rabies is a fox

B = reported case of rabies is a bat

O = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = x.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, $\sum P(X)=1$

Compute the value of x as follows:

$\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30$

Thus, the value of x is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

$P(A^{c})=1-P(A)$

Compute the probability that a reported case of rabies is not a raccoon as follows:

$P(R^{c})=1-P(R)\\=1-0.55\\=0.45$

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

$P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15$

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

4 0

3 years ago

Please help me with question 26

AleksAgata [21]

Answer: B) 65 degrees

-----------------------------------------------------

angle AEB = angle GEC
5x = 3x+10
5x-3x = 10
2x = 10
x = 5

angle GEC = 3x+10
angle GEC = 3*5+10
angle GEC = 25 degrees

Angle FEG = 90 - (angle GEC)
Angle FEG = 90 - 25
Angle FEG = 65 degrees

5 0

3 years ago

A researcher selects two samples of equal size and computes a mean difference of 1.0 between the two sample means. If the pooled

s344n2d4d5 [400]

Answer:

The Cohen's D is given by this formula:

$D = \frac{\bar X_A -\bar X_B}{s_p}$

Where $s_p$ represent the deviation pooled and we know from the problem that:

$s^2_p = 4$ represent the pooled variance

So then the pooled deviation would be:

$s_p = \sqrt{4}= 2$

And the difference of the two samples is $\bar X_a -\bar X_b = 1$ , and replacing we got:

$D = \frac{1}{2}= 0.5$

And since the value for D obtained is 0.5 we can consider this as a medium effect.

Step-by-step explanation:

Previous concepts

Cohen’s D is a an statistical measure in order to analyze effect size for a given condition compared to other. For example can be used if we can check if one method A has a better effect than another method B in a specific situation.

Solution to the problem

The Cohen's D is given by this formula:

$D = \frac{\bar X_A -\bar X_B}{s_p}$

Where $s_p$ represent the deviation pooled and we know from the problem that:

$s^2_p = 4$ represent the pooled variance

So then the pooled deviation would be:

$s_p = \sqrt{4}= 2$

And the difference of the two samples is $\bar X_a -\bar X_b = 1$ , and replacing we got:

$D = \frac{1}{2}= 0.5$

And since the value for D obtained is 0.5 we can consider this as a medium effect.

7 0

3 years ago

In a class if 20 students, 60% are girls. How many Students are girls?

seropon [69]

12 students are girls and 8 are boys.

6 0

3 years ago

help please !!!Kevin wants to make a mixture that is 50% lemon juice and 50% lime juice. How much 100% lemon juice should he add

Liula [17]

So basically, he wants to make mixture where lemon=lime

it is 6 gallons so
40% of 6=0.4 times 60=2.4=lemon
60% of 6=0.6 times 60=3.6=lime
so to make them equal
3.6-2.4=1.2
he must add 1.2 gallons of 100% lemon juice to make a mixture of 50% lemon and 50% lime

1.2 gallons is the answer

8 0

3 years ago

If someone could help! ​

If someone could help!