We are asked to determine the correlation factor "r" of the given table. To do that we will first label the column for "Quality" as "x" and the column for "Easiness" as "y". Like this:
Now, we create another column with the product of "x" and "y". Like this:
Now, we will add another column with the squares of the values of "x". Like this:
Now, we add another column with the squares of the values of "y":
Now, we sum the values on each of the columns:
Now, to get the correlation factor we use the following formula:

Where:

Now we substitute the values, we get:

Solving the operations:

Therefore, the correlation factor is 0.858. If the correlation factor approaches the values of +1, this means that there is a strong linear correlation between the variables "x" and "y" and this correlation tends to be with a positive slope.
Answer:
A. (0, -2) and (4, 1)
B. Slope (m) = ¾
C. y - 1 = ¾(x - 4)
D. y = ¾x - 2
E. -¾x + y = -2
Step-by-step explanation:
A. Two points on the line from the graph are: (0, -2) and (4, 1)
B. The slope can be calculated using two points, (0, -2) and (4, 1):

Slope (m) = ¾
C. Equation in point-slope form is represented as y - b = m(x - a). Where,
(a, b) = any point on the graph.
m = slope.
Substitute (a, b) = (4, 1), and m = ¾ into the point-slope equation, y - b = m(x - a).
Thus:
y - 1 = ¾(x - 4)
D. Equation in slope-intercept form, can be written as y = mx + b.
Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.
y - 1 = ¾(x - 4)
4(y - 1) = 3(x - 4)
4y - 4 = 3x - 12
4y = 3x - 12 + 4
4y = 3x - 8
y = ¾x - 8/4
y = ¾x - 2
E. Convert the equation in (D) to standard form:
y = ¾x - 2
-¾x + y = -2
4.05x10^5 km^<span>2 is the answer to your question.
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Answer:
C. f(x) = x - 7 all over 4
Step-by-step explanation:
NB: Let f(x) = y
Exchange X and Y
Make y the subject
f(x) = 4x + 7
y = 4x + 7
x = 4y + 7
x - 7 = 4y
x - 7 all over 4 = 4 ÷ 4
y = x - 7 all over 4
wish i did, i'm bored as well