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Alex777 [14]
4 years ago
10

 If a sphere has a circumference of 138.16 ​in., what is the surface area of the​ sphere?

Mathematics
1 answer:
BigorU [14]4 years ago
5 0
The surface area is 6075.96 in^3
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16 ?

Step-by-step explanation:

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3 years ago
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Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe
bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W  = 100 m

The  largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES  = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter  

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W)   - L  = 2W + L

Now, fencing is given as 500 m

⇒  2W + L  = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L =  2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W  = 100 m

The maximized area = Length x Width

                                   = 200 m x 100  m = 20, 000 sq m

Hence, the  largest area that can be enclosed is 20,000 sq m.

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3 years ago
Mount McKinley, the highest mountain in North
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Since the deepest point of Death Valley is below sea level, its altitude is negative. So, the difference between the altitudes is

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3 years ago
29) Find the area of a right triangle with a base of 22 cm and height of 10 cm.
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110 cm²

Step-by-step explanation:

The area of a triangle is 1/2 times base times height.

A = 1/2bh

A = 1/2(22)(10)

A = 110

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3 years ago
Sqrt of 4a-4 + sqrt of a-1
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\large\begin{array}{l} \textsf{Simplify the expression (I'm goint to call it E)}\\\\ \mathsf{E=\sqrt{4a-4}+\sqrt{a-1}} \end{array}


\large\begin{array}{l} \textsf{So E is a sum of two square roots. Notice that you can factor}\\\textsf{the 4 out on the first one:}\\\\ \mathsf{E=\sqrt{4\cdot a-4\cdot 1}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{4\cdot (a-1)}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{2^2\cdot (a-1)}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{2^2}\cdot \sqrt{a-1}+\sqrt{a-1}}\\\\ \mathsf{E=2\cdot \sqrt{a-1}+\sqrt{a-1}} \end{array}

\large\begin{array}{l} \mathsf{E=2\cdot \sqrt{a-1}+1\cdot \sqrt{a-1}}\\\\ \mathsf{E=(2+1)\cdot \sqrt{a-1}}\\\\ \boxed{\begin{array}{l}\mathsf{E=3\cdot \sqrt{a-1}} \end{array}} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2179170


\large\textsf{I hope this helps. :-)}


Tags: <em>square root sqrt simplify expression radical irrational algebra</em>

5 0
3 years ago
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