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Zigmanuir [339]
3 years ago
14

What is the distance between the two points located at (3, 8) and (10,8)? PLS HELP!!!

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

7

Step-by-step explanation:

distance formula

Komok [63]3 years ago
5 0

Answer:

i need a graph so my educated guess is 7

Step-by-step explanation:

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Find the volume of the following<br> square pyramid.<br> 5 cm<br> 5 cm<br> 5 cm
yanalaym [24]

Answer:

41.7

Step-by-step explanation:

4 0
3 years ago
-2 2/3 divided by 4/3
Vedmedyk [2.9K]

Answer:

-2

Step-by-step explanation:

Rule(s): a\frac{b}{c} = \frac{a \cdot c + b}{c}, \frac{-a}{b}=-\frac{a}{b}, \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c} \\2\frac{2}{3}=\frac{2\cdot 3+2}{3}\\=\frac{8}{3}\\=\frac{-\frac{8}{3}}{\frac{4}{3}}\\=-\frac{\frac{8}{3}}{\frac{4}{3}}\\=\frac{-8\cdot \:3}{3\cdot \:4}\\= \frac{-24}{12}\\= -2

8 0
1 year ago
PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE Please help please
umka21 [38]
The correct answer is:  "(-1, -2)" .
________________________________________
Note:  By examining the point of intersection of the lines of the 2 graphs show in the "image attached", we can see that the point of intersection is at:  "(-1, 2");  that is:  "x = -1, y = 2" .
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3 0
3 years ago
Read 2 more answers
On a spinner, there are twenty equal-size sections numbered from 1 to 20. Which spinner game is fair? Show your work.
Anvisha [2.4K]

The spinner game is an illustration of probability, and the spinner game that is fair is (b) If you spin a number greater than 10, you win.

<h3>How to determine the fair game?</h3>

The number of sections in the spinner is given as:

n = 20

There are 10 numbers greater than 10 i.e. 11 to 2.

So, the probability that a number greater than 10 is spun is:

P = 10/20

P = 0.5

The probability that a number that is not greater than 10 is spun is calculated using the following complement rule

q = 1 - p

This gives

q = 1 - 0.5

Evaluate

q = 0.5

Notice that both probabilities are the equal

Hence, the spinner game that is fair is (b) If you spin a number greater than 10, you win.

Read more about probability at:

brainly.com/question/3581617

5 0
2 years ago
Two machines are used for filling plastic bottles to a net volume of 16.0 ounces. A member of the quality engineering staff susp
aleksandrvk [35]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the two machines are filling the bottles with a net volume of 16.0 ounces or if at least one of them is different.

The parameter of interest is μ₁ - μ₂, if both machines are filling the same net volume this difference will be zero, if not it will be different.

You have one sample of ten bottles filled by each machine and the net volume of the bottles are measured, determining two variables of interest:

Sample 1 - Machine 1

X₁: Net volume of a plastic bottle filled by the machine 1.

n₁= 10

X[bar]₁= 16.02

S₁= 0.03

Sample 2 - Machine 2

X₂: Net volume of a plastic bottle filled by the machine 2

n₂= 10

X[bar]₂= 16.01

S₂= 0.03

With p-values 0.4209 (for X₁) and 0.6174 (for X₂) for the normality test and using α: 0.05, we can say that both variables of interest have a normal distribution:

X₁~N(μ₁;δ₁²)

X₂~N(μ₂;δ₂²)

Both population variances are unknown you have to conduct a homogeneity of variances test to see if they are equal (if they are you can conduct a pooled t-test) or different (if the variances are different you have to use the Welche's t-test)

H₀: δ₁²/δ₂²=1

H₁: δ₁²/δ₂²≠1

α: 0.05

F= \frac{S^2_1}{S^2_2} * \frac{Sigma^2_1}{Sigma^2_2} ~~F_{n_1-1;n_2-1}

Using a statistic software I've calculated the test

F_{H_0}= 1.41

p-value 0.6168

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis then you can conclude that both population variances for the net volume filled in the plastic bottles by machines 1 and 2 are equal.

To study the difference between the population means you can use

t= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~~t_{n_1+n_2-2}

The hypotheses of interest are:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

Sa= \sqrt{\frac{(n_1-1)S^2_1+(N_2-1)S^2_2}{n_1+n_2-2}} = \sqrt{\frac{9*9.2*10^{-4}+9*6.5*10^{-4}}{10+10-2} } = 0.028= 0.03

t_{H_0}= \frac{(16.02-16.01)-0}{0.03*\sqrt{\frac{1}{10} +\frac{1}{10} } } = 0.149= 0.15

The p-value for this test is: 0.882433

The p-value is greater than the significance level, the decision is to not reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to reject the null hypothesis. You can conclude that the population average of the net volume of the plastic bottles filled by machine one and by machine 2 are equal.

I hope this helps!

8 0
3 years ago
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