Answer:
The position at time t is 
Step-by-step explanation:
From the question we are told that
The acceleration is 
The velocity at t = 0 is 
The position at time t = 0 is 
Generally acceleration is mathematically represented as
=> 
=> 
integrating both sides we have
=> 
Now at t = 0
=> 
So
Generally the position of the body is mathematically represented as
So
So
Now at t = 0
=> 
So
The first answer is -3 !!
Answer:
I guess that you want to find the profit:
We have two equations:
the cost equation:
C(x) = -0.1*x^2 + 100.
And the selling equation, that is a vertical stretch of the cost equation by a factor of 1.4:
S(x) = 1.4*C(x) = 1.4*( -0.1*x^2 + 100.) = -0.14*x^2 + 140
Now, whit those two equations we can find the profit equation, that is defined as the difference between the selling price, and the cost:
P(x) = S(x) - C(x) = 1.4*C(x) - C(x) = (1.4 - 1)*C(x) = 0.4*C(x).
Then the profit is 0.4 times the initial cost.
P(x) = 0.4*( -0.1*x^2 + 100.) = -0.04*x^2 + 40
Answer:
It's C :)
Step-by-step explanation:
Next time check the y-intercept
Green has a intercept of 1
and purple has -3
Remember PEMDAS.
So, multiplication first.
4+16-5.
Then, addition and subtraction.
20-5.
15.
The answer is 15.
