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Korvikt [17]
3 years ago
9

Can somebody help me answer this please

Mathematics
1 answer:
loris [4]3 years ago
3 0
1. The product of 23 times f. 3. Five times m to the second power plus 2 or the product of four and m to the second power plus two. 4. four times n to the second power divided by 7 or the product of four and n to the second power divided by 7.  2.  The difference of 4 times d to the third power and 10.  I hope this helps.  I'm not positive I'm right, but I might be.
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Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
Read 2 more answers
Help quickly! A student wants to report on the number of movies her friends watch each week. The collected data are below:
max2010maxim [7]
1.The measure of center that is most appropriate for this situation is the MEDIAN. This is because, one of the number given is an outlier, that is, it is much greater than the rest of the given numbers. If the mean of the number given is calculated, it will be discovered that the mean value obtained is higher than most of the scores in the data set, thus,the mean is not a suitable measure of central tendency in this case.
2. To find the median of the given numbers, arrange them in a descending order and add the two numbers in the middle then divide the value by 2.
That is, 0, 0, 1, 1, 2, 2, 2, 14.
The two numbers in the middle is 1 and 2.
 Median = [1 + 2] / 2 = 3/2 = 1.5
Therefore, the median is 1.5
6 0
3 years ago
I really need help please.
love history [14]

Answer:

64

Step-by-step explanation:

6 0
3 years ago
4x^2 + n (n+x) x=3 n=5
Vika [28.1K]
Mm dont know but keep trying

3 0
3 years ago
If a + b = 15, find the maximum value of a × b​
Otrada [13]

Answer: 56

Step-by-step explanation:

8 0
3 years ago
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