The area of a rhombus is 1/2 times the lengths of the diagonals
A = (1/2)(AC)(BD)
Since the diagonals bisect each other, and ed = 8, BD must be 16. Substituting in this for BD and the given area (168) we get the following:
168 = (1/2)(AC)16
168 = 8(AC)
21 = AC
Answer:
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Your answer would be <em><u>2*10^2 + 1*10^1 + 5*1^1</u></em>
