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2 years ago

A triangle has side lengths of (5k - 7) centimeters, (k - 4) centimeters, and

Mathematics

1 answer:

Yuki888 [10]2 years ago

7 0

Answer:

-6m and -6k

Step-by-step explanation:

(5k - 7) = -2k (k - 4) = -4k + -2k = -6k. (3m - 9) = -6m.

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Qualitative methods are primarily based on numerical data importance of research observations the number of surveys returned sta

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False. This describes quantitative methods

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3 years ago

A $320 suit is marked down by 10%. Find the sale price.<br> Please help

puteri [66]

Answer: it costs $288, I hope this answers your question:)

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3 years ago

Read 2 more answers

A) What are the coordinates of the image of vertex G after a reflection across the line y = x?

Oksanka [162]

Answer:

b. (-5, 4)

Step-by-step explanation:

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3 years ago

Hey! I have some geometry questions today!

Volgvan

Answer:

Step-by-step explanation:

<h3>Question 1</h3>

It is assumed the chords have equal length: PQ = SR

If the vertexes connected with the center, the both chords will form a right triangle, with the hypotenuse being the radius.

<u>Then the radius is found using Pythagorean theorem:</u>

r = $\sqrt{20^2 + 21^2}$ = $\sqrt{841}$ = 29

<h3>Question 2</h3>

<u>Use the intersecting secants theorem: and solve for x:</u>

FS*FT = FP*FQ
4(4 + x) = 5(5 + 3)
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8 0

2 years ago

I need to know how to do the whole thing and understand it.

patriot [66]

We are given the data on the number of candies handed by neighborhood A and neighborhood B.

Let us first find the mean and variance of each neighborhood.

Mean:

$\bar{x}_A=\frac{\sum x}{N_1}=\frac{12}{6}=2$ $\bar{x}_B=\frac{\sum x}{N_2}=\frac{20}{6}=3.33$

Variance:

$s_A^2=\frac{\sum x^2}{N_1}-\bar{x}_A^2=\frac{28}{6}-2^2=0.667$ $s_B^2=\frac{\sum x^2}{N_2}-\bar{x}_B^2=\frac{80}{6}-3.33^2=2.244$

A. Null hypothesis:

The null hypothesis is that there is no difference in the mean number of candies handed out by neighborhoods A and B.

$H_0:\;\mu_A=\mu_B$

Research hypothesis:

The research hypothesis is that the mean number of candies handed out by neighborhood A is more than neighborhood B.

$H_a:\;\mu_A>\mu_B$

Test statistic (t):

The test statistic of a two-sample t-test is given by

$t=\frac{\bar{x}_A-\bar{x}_B}{s_p}$

Where sp is the pooled standard deviation given by

$\begin{gathered} s_p=\sqrt{\frac{N_1s_1^2+N_2s_2^2}{N_1+N_2-2}(\frac{N_1+N_2}{N_1\cdot N_2}}) \\ s_p=\sqrt{\frac{6\cdot0.667+6\cdot2.244}{6+6-2}(\frac{6+6}{6\cdot6})} \\ s_p=0.763 \end{gathered}$ $t=\frac{2-3.33}{0.763}=-1.74$

So, the test statistic is -1.74

Critical t:

Degree of freedom = N1 + N2 - 2 = 6+6-2 = 10

Level of significance = 0.05

The right-tailed critical value for α = 0.05 and df = 10 is found to be 1.81

Critical t = 1.81

We will reject the null hypothesis because the calculated t-value is less than the critical value.

Interpretation:

This means that we do not have enough evidence to conclude that neighborhood A gives out more candies than neighborhood B.

6 0

1 year ago